FIND Za, FOR THE 94% /2 CONFIDENCE INTERVAL
Q: A survey of 800 women shoppers found that 17% of them shop on impulse what is the 98% confidence…
A: Sol:- To calculate the 98% confidence interval for the proportion of women shoppers who shop on…
Q: In Cleveland, a random sample of 74 mail carriers showed that 12 had been bitten by an animal during…
A:
Q: Express the confidence interval (68 % , 79.6 % ) in the form of p + ME.
A: The mid-point of the confidence interval gives the value of p-cap.
Q: A certain study sampled 1283 adults about drinking coffee. The study showed that 824 of the adults…
A: Givensample size(n)=1283x=824confidence level=95%
Q: Whenever an effect is significant, all values in the confidence interval will move in which…
A: The confidence level indicates the possibility that the confidence interval contains the population…
Q: A random survey of 70 male sophomores showed 16 preferred off campus living and out of 63 female…
A:
Q: Express the confidence interval (48.7 % , 58.5 % ) in the form of p ± E.
A: Given information confidence interval (48.7%,58.5%)
Q: Out of 400 people sampled, 32 had kids. Based on this, construct a 95% confidence interval for the…
A: Solution: Let X be the number of people had kids and n be the sample number of people. From the…
Q: Out of a sample of 150 people who walked into a fast food restaurant, 135 said they prefer ketchup…
A:
Q: Express the confidence interval 27.1%±8.5%27.1%±8.5% in interval form.
A: The given confidence interval is 27.1%±8.5%.
Q: Express the confidence interval 81.9%. ±. 4.6%. in interval form.
A: Confidence interval is the estimate of the interval of an unknown population parameter. It provides…
Q: he lower end of the 95% confidence interval is Question Blank 1 of 2and the higher end of the 95%…
A: n=8 Sample sizex= 9.8 Sample mean s= 0.4 Sample standard deviation
Q: Determine from a confidence interval whether a test is significant?
A: Null hypothesis states that there is no difference between populations or a set of given…
Q: Express the confidence interval (74.6%,82.4%)in the form of ˆp±ME
A:
Q: A survey of 100 customers showed that 36 of them preferred brand B of a particular product. Give a…
A: p = proportion of people vote for BSample size : n = 100Number of favorable outcomes : x =…
Q: 324 out of a simple random sample of 400 students hated their online math course. Find a 99%…
A: Given: Number of students that hated the online math course (y) = 324 Number of students (n) = 400…
Q: In a sample of 550 adults, 512 had children. Construct a 99% confidence interval for the true…
A: Given X=512 n=550
Q: Joe’s Pizza Joint found that 64.2% of the 328 pizzas sold last week included pepperoni. Find a98%…
A: Obtain the 95% confidence interval for the proportion of Joe’s customers that order pepperoni. The…
Q: In a random sample of 500 Americans, 50% indicated that they have a cat for a pet. Estimate with 95%…
A: Given information
Q: Express the confidence interval (45.7 % , 59.5 % ) in the form of p + ME.
A: From the provided information, Confidence interval is (45.7%, 59.5%)
Q: An internet service provider sampled 1000 of its customers, 189 of them experienced an interruption…
A: It is given that sample size (n) is 1000 and x is 189.
Q: Express the confidence interval 27.3%±8.3%27.3%±8.3% in interval form.
A: Given that, Confidence Interval = 27.3% ± 8.3%
Q: A sample of 400 homeowners includes 124 that expect their home to increase in value in the next…
A: Margin of error: ME=Zα/2 * √p̂(1-p̂)/n
Q: A study of 156 oak trees found that 8.5% had a bark beetle infestation. Find a 95%…
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Q: A scientist claims that 65% of U.S. adults believe humans contribute to an increase in global…
A: Given A scientist claims that 65% of U.S. adults believe humans contribute to an increase in global…
Q: Out of 400 people sampled, 260 had kids. Based on this, construct a 90% confidence interval for the…
A: Given that, x=260,n=400 The sample proportion is, Critical values: By using the standard normal…
Q: Out of 300 people sampled, 111 had kids. Based on this, construct a 95% confidence interval for the…
A: The objective of this question is to construct a 95% confidence interval for the true population…
Q: 980 adults to learn about their gym membership. The results showed that 574 of the respondents lack…
A: The random variable X follows normal distribution. We have to construct 95% confidence interval for…
Q: A recent study by the McGraw-Hill company showed that 61% (1621) of college students use their…
A: Given, Proportion of college students use their smartphones for study = 0.61Total number of students…
Q: In a sample of 900 people, 378 say they snooze the alarm more than once in the morning. Find a 95%…
A: Given, The sample proportion is,
Q: Express the confidence interval 20.1%<p<33.1% in the form of ˆp±E.
A:
Q: Express the confidence interval (70.4%,80.4%) in the form of ˆp±ME
A: It is given that the confidence interval is (70.4%, 80.4%).
Q: Express the confidence interval 83.2%±7.2%83.2%±7.2% in interval form.
A: It is given that, The confidence interval is 83.2% ± 7.2%. We have to write the given confidence…
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- In a sample of 460 adults, 281 had children. Construct a 90% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three places < p <A random sample of 120 rhesus monkeys found that the number of rhesus monkeys that live in a captive breeding facility is 77. Construct a 90% confidence interval for the true proportion of rhesus monkeys that live in a captive breeding facility.Express the confidence interval 57.2 % Next Question
- FIND Za/2 FOR THE 86 % CONFIDENCE INTERVAL2A researcher investigated whether the temperature of milk, x, can be used to predict the milk's pH content, y. She predicted the pH level of a glass of milk with a temperature of 8.45 degrees to be ŷ= 6.795 a)A 95% confidence interval for the mean pH of all milk with temperature 8.45 degrees is calculated to be (6.76, 6.83). Which of the following is the correct interpretation of this confidence interval? -The mean pH level for all glasses of milk having a temperature of 8.45 degrees is somewhere between 6.76 and 6.83, with 95% confidence. -The pH level for one glass of milk with a temperature of 8.45 degrees is somewhere between 6.76 and 6.83, with 95% confidence. -There is a probability of 0.95 that the mean pH level for this glass of milk with temperature 8.45 degrees is between 6.76 and 6.83. -95% of all glasses of milk with a temperature of 8.45 degrees have a pH level between 6.76 and 6.83. b)Suppose we have a glass of milk whose temperature is 8.45 degrees. We…
- In a sample of 360 adults, 266 had children. Construct a 95% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three placesThe general form of a confidence interval is inferred asIn a sample of 510 adults, 281 had children. Construct a 95% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three placesRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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