Express the confidence interval 57.2 % Next Question
Q: In a city, out of 200 people sampled, 152 had kids. Based on this, construct a 95% confidence…
A: Find z-critical value: For the two-tail test, Area on each tail. Area to the left of the normal…
Q: In a sample of 120 adults, 114 had children. Construct a 99% confidence interval for the true…
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Q: Express the confidence interval 14.4<p<28.4% in the form of p+-ME %+- %
A: Point estimate p-hat: The formula for point estimate is,
Q: Express the confidence interval (0.069, 0.143) in the form of p - E <p <p + E
A: Given that, Confidence interval = (0.069, 0.143)
Q: Out of 300 people sampled, 258 had kids. Based on this, construct a 99% confidence interval for the…
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Q: Express the confidence interval 87.8 % + 3.4 % in interval form Express the answer in decimal format…
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Q: Express the confidence interval (80%,97.6%)(80%,97.6%) in the form of ˆp±E
A: The confidence interval is given by (80%, 97.6%) and it can be written as (0.80, 0.976)
Q: In a sample of 270 adults, 151 had children. Construct a 90% confidence interval for the true…
A: Given that Sample size n =270 Favorable cases x =151 Sample proportion p^=x/n =151/270 =0.5593
Q: Express the confidence interval (55.6%,69.6%) in the form of ˆp±ME then express it in trilnear…
A: It is given that , The confidence interval =(55.6%,69.6%) Aim: To obtain the confidence interval in…
Q: Express the confidence interval 0.333 <p<0.777 in the form p+ E.
A: We have to solve given problem:
Q: You are interested in finding a 90% confidence interval for the mean number of visits for physical…
A: Given observation 27 18 26 18 16 20 10 20 19 19 28 14 27
Q: Express the confidence interval 11.5 % ± 8.6 % in interval form. Express the answer in decimal…
A: Given : confidence interval = 11.5 % ± 8.6 %
Q: Express the confidence interval 30.1%<p<41.5% in the form of p+_E
A: given data, confidence interval 30.1%<p<41.5%p±E=?
Q: Express the confidence interval 85.2% ± 4% in interval form. Express the answer in decimal format…
A: Given confidence interval is 85.2% ± 4% We have to answer in decimal form
Q: Express the confidence interval 0.444<p<0.888 in the form p+ E.
A: Obtain the point estimate of the proportion. The point estimate of the proportion is obtained…
Q: Express the confidence interval (74.6%,82.4%)in the form of ˆp±ME
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Q: Give your answers as decimals, to three places. We can write this answer as OR F It < p <
A: It is given that Favourable cases, X = 162 Sample size, n = 300 Sample proportion, p^ = X/n = 0.54
Q: Express the confidence interval 42.5 % < p < 48.5% in the form of pE. % + Submit Question
A: According to the given information in this question We need to write in the form of given in this…
Q: Express the confidence interval (64.5%,70.7%)(64.5%,70.7%) in parts ˆp and E ˆp= __ (use decimals…
A: The confidence interval is (64.5%, 70.7%).
Q: Express the confidence interval 563.8
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Q: Out of 500 people sampled, 355 had kids. Based on this, construct a 90% confidence interval for the…
A: By using the given information, we have Out of 500 people sampled, 355 had kids. 90% confidence…
Q: Out of 300 people sampled, 207 had kids. Based on this, construct a 90% confidence interval for the…
A: Givensample size(n)=300x=207sample proportion(p^)=xn=207300=0.69confidence level=90%
Q: Out of 600 people sampled, 492 had kids. Based on this, construct a 99% confidence interval for the…
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Q: In a sample of 420 adults, 349 had children. Construct a 90% confidence interval for the true…
A: given data sample size (n) = 420favorable outcomes (x) = 34990% ci p.
Q: If n = 420 and ˆpp^ (p-hat) = 0.75, construct a 99% confidence interval. Give your answers to three…
A: Solution: From the given information, p-hat=0.75 and n=420. The confidence level is 0.99.
Q: Out of 200 people sampled, 132 had kids. Based on this, construct a 90% confidence interval for the…
A: given data, x=132n=200CI=0.90α=1-0.90=0.10p^=xn=132200=0.66
Q: Express the confidence interval 75.7% < p < 85.1% in the form of p± E. %+ Submit Question
A: We have given Information, Confidence interval for population proportion p is: 75.7%<p<85.1%…
Q: In a sample of 300 adults, 267 had children. Construct a 90% confidence interval for the true…
A: To construct a 90% confidence interval for the population proportion, we'll use the formula for the…
Q: Express the confidence interval 57.2 % < p < 71.4 % in the form of p + E. % +
A: From the provided information Confidence interval 57.2% < p < 71.4%
Q: onfidence interval (80.6%,94%)(80.6%,94%) in the form of ˆp±Ep^±E.
A: Given that Confidence interval = ( 80.6% , 94%) = (0.806 , 0.94) We know that Confidence…
Q: Express the confidence interval 84.4%±4%84.4%±4% in interval form. Express the answer in decimal…
A: We have given that, the confidence interval 84.4%±4%84.4%±4% in interval form. Then, We will find…
Q: Express the confidence interval 29%<p<44.2%in the form of ˆp±E
A: Therefore,
Q: t of 300 people sampled, 237 had kids. Based on this, construct a 90% confidence interval for the…
A: given data, n=300x=had kids=237p^=xn=237300=0.79CI=0.90α=1-0.90=0.10
Q: Express the confidence interval (17.7%,34.5%)(17.7%,34.5%) in the form of ˆp±Ep^±E.
A: Confidence Interval: Confidence interval is the interval estimate of the population parameter. It is…
Q: Out of 500 people sampled, 245 had kids. Based on this, construct a 95% confidence interval for the…
A: From the provided information, Out of 500 people sampled, 245 had kids. That is x = 245 and n = 500…
Q: If n-350 and (p-hat) -0.88, find the margin of error at a 95% confidence level Give your answer as a…
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Q: Out of 300 people sampled, 258 had kids. Based on this, construct a 99% confidence interval for the…
A:
Q: Express the confidence interval 0.222 <p< 0.444 in the form p+E.
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Q: Out of 500 people sampled, 415 had kids. Based on this, construct a 95% confidence interval for the…
A:
Q: If n = 200 and ˆpp^ (p-hat) = 0.85, construct a 95% confidence interval. Give your answers to three…
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- Out of 100 people sampled, 68 had kids. Based on this, construct a 95% confidence interval for the true population proportion of people with kids.Give your answers as decimals, to three places < p <Out of 100 people sampled, 82 had kids. Based on this, construct a 95% confidence interval for the true population proportion of people with kids. Give your answers as decimals, to three places.Express the confidence interval (0.074, 0.120) in the form of p̂ - E<p<p̂ +E what should replace the question marks? Do not round. ? < p < ?Recommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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