The confidence interval with mean value 2 and margin error is 1.3 is
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The confidence interval with
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- To calculate 95% confidence interval we must multiply the standard error by 3, then add and subtract the result to the best estimate. add and subtract the standard error to the best estimate. multiply the standard error in y-intercept by 2, then add and subtract the result to the slope of the graph. multiply the standard error by 2, then add and subtract the result to the best estimate.A researcher collected sample data for 19 middle-aged women. The sample had a mean serum cholesterol level (measured in milligrams per one hundred milliliters) of 192.4, with a standard deviation of 8.2. Assuming that serum cholesterol levels for middle-aged women are normally distributed, find a 90% confidence interval for the mean serum cholesterol level of all women in this age group. Give the lower limit and upper limit of the 90% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. (If necessary, consult a list of formulas.) Lower limit: Upper limit:A researcher collected sample data for 19 middle-aged women. The sample had a mean serum cholesterol level (measured in milligrams per one hundred milliliters) of 190.3, with a standard deviation of 9.5. Assuming that serum cholesterol levels for middle-aged women are normally distributed, find a 95% confidence interval for the mean serum cholesterol level of all women in this age group. Give the lower limit and upper limit of the 95% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. (If necessary, consult a list of formulas.) Lower limit= Upper limit=
- An article claims that babies spend twice as much time in REM (rapid eye movement) sleep than adults. This implies that babies have an average of 6 hours of REM sleep per night. A doctor would like to test the hypotheses = 6 versus ≠ 6 where = the true mean amount of REM sleep per night for babies. A 95% confidence interval for the true mean amount of REM sleep per night for babies is (5.45, 6.25) hours. Based on the confidence interval, what conclusion would you make for a test of these hypotheses? The 95% confidence interval include as a plausible value, so we H0. We convincing evidence that the true mean amount of REM sleep per night for babies 6 hours.The 99% confidence interval on a population mean computed with a sample of size 36 and sample mean 1.4 is computed knowing that the standard deviation of this population is 0.3. The margin of error for this confidence interval is aboutFind the level of the confidence interval that has the value Za/2 = 1.28. (Round the final answer to three decimal places.)
- A city planner wants to estimate the average monthly residential water usage in the city. He selected a random sample of 42 households from the city, which gave the mean water usage to be 3409.30 gallons over a one-month period. Based on earlier data, the population standard deviation of the monthly residential water usage in this city is 387.90 gallons. Make a 97% confidence interval for the average monthly residential water usage for all households in this city.Suppose that a jewelry store tracked the amount of emeralds they sold each week to more accurately estimate how many emeralds to keep in stock. At the end of one year, the store used the weekly sales information to construct a 95% confidence interval for the mean number of emeralds sold per week. The confidence interval they calculated was (3.25,4.51). Use the confidence interval to find the point estimate for the mean and the margin of error. Give your answers precise to two decimal places.A researcher collected sample data for 15 middle-aged women. The sample had a mean serum cholesterol level (measured in milligrams per one hundred milliliters) of 192.7, with a standard deviation of 6. Assuming that serum cholesterol levels for middle-aged women are normally distributed, find a 99% confidence interval for the mean serum cholesterol level of all women in this age group. Give the lower limit and upper limit of the 99% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. (If necessary, consult a list of formulas.) Lower limit: Upper limit: X Ś
- A researcher collected sample data for 19 middle-aged women. The sample had a mean serum cholesterol level (measured in milligrams per one hundred milliliters) of 191.5, with a standard deviation of 6.5. Assuming that serum cholesterol levels for middle-aged women are normally distributed, find a 95% confidence interval for the mean serum cholesterol level of all women in this age group. Give the lower limit and upper limit of the 95% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. lower limit ____ Upper Limit ____A researcher collected sample data for 20 middle-aged women. The sample had a mean serum cholesterol level (measured in milligrams per one hundred milliliters) of 190.4, with a standard deviation of 9.7. Assuming that serum cholesterol levels for middle-aged women are normally distributed, find a 99% confidence interval for the mean serum cholesterol level of all women in this age group. Give the lower limit and upper limit of the 99% confidence interval.Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place Lower limit= Upper limit=If n=550 and p' (p-prime) = 0.19, construct a 90% confidence interval.Give your answers to three decimals.
