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If log K, for Ag(NH3)2* is 3.31 and log K2 is 3.91, what is K,?

If log K, for Ag(NH3)2* is 3.31 and log K2 is 3.91, what is K,?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Based on the first picture, answer the question on the second picture.

Formation of soluble silver-ammonium complex, in an AgCl solution, occurs in a 3-step process: AgCI(s)= Ag* (aq) + CH(aq) Ksp Ag*(aq) + NH3(aq) = AGNH3*(aq) K, AGNH3*(aq) + NH3(aq)= Ag(NH3)2"(aq) K2 where Kp is the solubility product for AgCl and K, & K2 are the equilibrium constants for the complex formation. The over-all formation constant (K;) for the Ag(NH3)2* complex is equal to K, x K2.
Transcribed Image Text:Formation of soluble silver-ammonium complex, in an AgCl solution, occurs in a 3-step process: AgCI(s)= Ag* (aq) + CH(aq) Ksp Ag*(aq) + NH3(aq) = AGNH3*(aq) K, AGNH3*(aq) + NH3(aq)= Ag(NH3)2"(aq) K2 where Kp is the solubility product for AgCl and K, & K2 are the equilibrium constants for the complex formation. The over-all formation constant (K;) for the Ag(NH3)2* complex is equal to K, x K2.
If log K, for Ag(NH3)2* is 3.31 and log K2 is 3.91, what is K,?
Transcribed Image Text:If log K, for Ag(NH3)2* is 3.31 and log K2 is 3.91, what is K,?
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