If in humans, brown eyes are dominant over green eyes, and twoheterozygous parents have three children, what is the probability that allof the kids will have green eyes?O 1.5%O 75%3%O 33% Suppose in flies, red eyes are dominant over brown eyes. If for this trait, ahomozygous dominant fly is mated with a heterozygous fly, what is theprobability that the fly will have brown eyes?100%0%50 %O 25%

Name: If in humans, brown eyes are dominant over green eyes, and twoheteroz
Uploaded: 2024-03-20T06:43:04.000Z
Channel: Bartleby
Description: If in humans, brown eyes are dominant over green eyes, and twoheterozygous parents have three children, what is the probability that allof the kids will have green eyes?O 1.5%O 75%3%O 33% Suppose in flies, red eyes are dominant over brown eyes. If f

In genetics, dominance refers to which of two alleles is expressed when the two differ. It's…

Answered: If in humans, brown eyes are dominant…

Science

Biology

If in humans, brown eyes are dominant over green eyes, and two heterozygous parents have three children, what is the probability that all of the kids will have green eyes?

Biology (MindTap Course List)

11th Edition

ISBN:9781337392938

Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg

Publisher:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg

Chapter11: The Basic Principles Of Heredity

Section: Chapter Questions

Problem 2TYU: The F1 flies described in question 1 were mated with brown-eyed flies from a true-breeding line....

See similar textbooks

Similar questions

(This one is more complicated). Two true breeding fruit flies are allowed to mate. One fly ishomozygous dominant for body color and eye color while the other is homozygous recessive forbody color and eye color. (g+:gray body, g:black body, e+:ebony eyes, e:red), The F1 flies areallowed to mate. What are the following probabilities in the F2 generation? For this problemmake sure to show the Punnett Square for your F2 generation and all of your calculations. Youdo not need to show the Punnett Square for the F1 generation. Answer in percent and round to 2decimals.a. Two of three fruit flies are gray and red.b. The first fruit fly is gray and ebony, the second fruit fly is gray and red, and the third fruit fly is black and ebony.
In fruit flies, the allele for normal wings (V) is dominant to the allele for short wings (v). Suppose two fruit flies heterozygous for the trait are mated. What is the male fruit fly’s genotype and the female fruit fly’s genotype? What is the male fruit fly’s phenotype and the female fruit fly’s phenotype? What will be the genotypic ratio of the F1 generation? What will be the phenotypic ration of the F1 generation?
For questions 1-3, consider a pea plant homozygous for tall stems and green seeds crossed with a plant dihybrid for tall stems and yellow seeds. ✓1. Determine the dimensions (minimum number of boxes) of the Punnett square needed to predict the likely outcome of this mating. O4x4 O 1x4 O 2x2 O1X5 ✓2. Determine the likelihood that this mating will generate progeny that exhibit tall stems. O 100% ● 50% 75% O25% ●0% 9 C
Coat color in mice is incompletely dominant. Yellow and white-colored mice are homozygous, while cream-colored mice are heterozygous. If two cream-colored mice mate, what phenotypic ratio can we expect of their offspring? Please show the solution.
BLACK VESTIGIAL DIHYBRID TESTCROSS In the parental generation, you mate a pure-breeding wild-type female (bl+/blt.vg+/vg+) with a pure-breeding black, vestigial (bl/bl vg/vg) to produce an F1 generation that is all wild-type (bl+/bl vg+/vg). Note that the F1 flies are all dihybrid. Next, you mate several F1 dihybrid females (bl+/bl vg+/vg) with tester males, which are black, vestigial (bl/bl;vg/vg). The offspring of this dihybrid testcross are: Phenotype Genotype Tester Gamete Dihybrid Gamete Number 440 Wild-type 394 108 135 Black, vestigial Vestigial Black Copy the table into your notes and derive the dihybrid gametes following the example in the previous section. The columns in blue (phenotypes and numbers of offspring) are what you can see and count. The genotypes of the testcross offspring (orange) must be deduced from the phenotypes and knowing that the tester contributed bl vg gametes. Finally, you can deduce the dihybrid gametes (green) by subtracting the tester gamete…
The F1 flies described in question 1 were mated with brown-eyed flies from a true-breeding line. What phenotypes would you expect the offspring to have? (a) all with red eyes (b) all with brown eyes (c) half with red eyes and half with brown eyes (d) red-eyed females and brown-eyed males (e) brown-eyed females and red-eyed males
Human females have two X chromosomes XX; males have one X and one Y chromosome XY. a. With respect to X-linked alleles, how many different types of gametes can a male produce? b. A female homozygous for an X-linked allele can produce how many types of gametes with respect to that allele? c. A female heterozygous for an X-linked allele can produce how many types of gametes with respect to that allele?
In a cross between a homozygous red-eyed female fruit fly and a white-eyed male fruit fly, what is the expected outcome? a. all white-eyed male offspring b. all white-eyed female offspring c. all red-eyed offspring d. half white-eyed make offspring
A man is homozygous dominant for ten different genes that assort independently. How many genotypically different types of sperm could he produce? A woman is homozygous recessive for eight of these genes and is heterozygous for the other two. How many genotypically different types of eggs could she produce? What can you conclude about the relationship between the number of different gametes possible and the number of heterozygous and homozygous gene pairs that are present?
In fruit flies, red eye color (R) is dominant over brown eye color (r). Two red-eyed fruit flies were mated and they produced the following offspring: 73 red-eyed flies; 27 brown-eyed flies. In the offspring, what is the approximate ratio of red-eyed to brown-eyed fruit flies?
n the fruit fly, Drosophila melanogaster, a spineless (sp, no wing bristles) female fly is mated to a male that is claret (cl, dark eyes) and hairless (h, no thoracic bristles). Phenotypically wild type F1 female progeny were mated to fully homozygous (mutant) males and the following progeny (1000 total) were observed. PHENOTYPES NUMBER OBSERVED spineless 266 wild 181 claret, spineless 18 claret 37 claret, hairless 264 hairless, claret, spineless 189 hairless 12 hairless, spineless 33…
Suppose that white is the dominant phenotype in sea slugs. Assuming simple dominance, what will be the result of a cross between P1 generation true-breeding lines of purple and white sea slugs? mostly purple sea slugs in the F1 generation, with an occasional white sea slug all purple sea slugs in the F1 generation, but a lighter purple than in the parents all white sea slugs in the F1 generation all purple sea slugs in the F1 generation