It is believed that large doses of acetaminophen (the active ingredient in over-the-counter pain relievers like Tylenol) may cause damage to the liver. A researcher wants to conduct astudy to estimate the proportion of acetaminophen users who have liver damage. For participating in this study, he will pay each subject $30 and provide a free medical consultation if thepatient has liver damage.(a) If he wants to limit the margin of error of his 98% confidence interval to 3%, what is the minimum amount of money he needs to set aside to pay his subjects? (Round your answerto the nearest dollar.)

Answered: Image /qna-images/answer/ae2b2adf-0f81-4dda-80fc-98d708738a83.jpg

Answered: If he wants to limit the margin of…

If he wants to limit the margin of error of his 98% confidence interval to 3%, what is the minimum amount of money he needs to set aside to pay his subjects?

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A simple random sample of 450 residents in the state of New York is taken to estimate the proportion of people who live within 1 mile of a hazardous waste site. If a 95% confidence interval were calculated for a scenario where p = 0.3 and another scenario where p = 0.7, how would the two confidence intervals compare? This cannot be determined from the information given. Since the sample proportion in the second scenario is larger, its confidence interval would be shifted to the right and narrower than the one calculated from the first scenario. Even though the sample proportions are different, the widths of the confidence intervals would be equal. Since the sample proportion in the first scenario is smaller, its confidence interval would be narrower.
The managers of an outdoor coffee stand in Coast City are examining the relationship between coffee sales and daily temperature. They have bivariate data detailing the stand's coffee sales (denoted by y, in dollars) and the maximum temperature (denoted by x, in degrees Fahrenheit) for each of 38 randomly selected days during the past year. The least-squares regression equation computed from their data is y = 2520.46 – 11.04.x. Tommorrow's forecast high is 66 degrees Fahrenheit. The managers have used the regression equation to predict the stand's coffee sales for tomorrow. They now are interested in both a prediction interval for tomorrow's coffee sales and a confidence interval for the mean coffee sales on days on which the maximum temperature is 66 degrees Fahrenheit. They have computed the following for their data. • mean square error (MSE) = 2624.44 2 (66-x) 1 z 0.0468, wherex¡, x2, X3g denote temperatures in the sample, and x denotes their mean 38 38 1' 2 i = 1 Based on this…
Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find the bone density test scores that can be used as cutoff values separating the lowest 10% and highest 10%, indicating levels that are too low or too high, respectively. Sketch the region containing the lowest 10% and highest 10%. Choose the correct graph below. OA. -Za Za Q The bone density scores are ☐ OB. -Za Za (Use a comma to separate answers as needed. Round to two decimal places as needed.) ○ C. Q Za -Za D. Q a G Za -Za
A Gallup poll asked a random sample of U.S. adults, “Would you like to lose weight?” Based on this poll, the 95% confidence interval for the population proportion who want to lose weight is (0.56, 0.62). How would the width of a 95% confidence interval based on a sample size four times as large compare to the original 95% interval, assuming the sample proportion remained the same? The length of the interval would be half as wide. The length of the interval would increase. The length of the interval would be one-fourth as wide. The length of the interval would stay the same. The length of the interval would double.
If n=19, (x-bar)=31, and s=9, find the margin of error at a 80% confidence level Give your answer to two decimal places.
If n = 220, p-hat = 0.4, then what will be the 90% Confidence Interval for the population proportion?
Beth wants to determine a 90 percent confidence interval for the true proportion p of high school students in the area who attend their home basketball games. Out ofn randomly selected students she finds that that exactly half attend their home basketball games. About how large would n have to be to get a margin of error less than 0.04 for p?
Now you are interested in the percent of dogs that were neutered in your sample. For 40 dogs, 30 of them were neutered. What is the LOWER limit for this confidence interval? The statistical value you will need is 1.96. Give your answer as 0.XX
If n=29, x=35, and s=2, find the margin of error at a 95% confidence level using the critical value rounded to three decimal places. Give your answer as an equation or as a number rounded to three decimal places.
if n=20, x=43, and s=9, construct a confidence interval at a 98% confidence level, the data came from a normally distributed population.
suppose that you take 1000 simple random samples from a population and that, for each sample, you obtain a 95% confidence interval for an unknown parameter. Approximately how many of those confidence intervals will continue the value of the unknown parameter?
Males and females were asked what they would do if they received a $100 bill in the mail that was addressed to their neighbor, but had been incorrectly delivered to them. Of the 70 males sampled, 55 said yes they would return it to their neighbor. Of the 130 females sampled, 120 said yes. We want to construct a 90% confidence interval estimate for the difference between the true proportion of males who say they would return the money to their neighbor and the true proportion of females who say they would return the money to their neighbor. Choose the best option for the result of constructing that interval. O -226 < p1 -p2 < +.003 O-226 < p1 -p2 <.-.048 O -243 < p1 -p2 < -.031