### Finding the Margin of Error at an 80% Confidence LevelGiven the following sample data:- Sample size (n) = 19- Sample mean (x̄) = 31- Sample standard deviation (s) = 9You are required to find the margin of error at an 80% confidence level. Please provide your answer to two decimal places.### Calculation Steps1. **Determine the critical value (t*)**: - For an 80% confidence level and a sample size of 19, you need to find the degrees of freedom (df), which is n - 1. Therefore, df = 19 - 1 = 18. - You can look up the critical value (t*) for an 80% confidence level and 18 degrees of freedom using a t-distribution table or calculator.2. **Calculate the standard error (SE)**: - SE = s / √n - Substitute the given values: SE = 9 / √193. **Calculate the Margin of Error (ME)**: - ME = t* × SE - Use the critical value obtained from the t-distribution table and the standard error calculated in the previous step.Once you calculate the above values, you'll have the margin of error rounded to two decimal places.#### Graphical Explanation(Since no graph or diagram is provided in the image, here is an explanation you could provide if relevant):A t-distribution graph can help visualize the concept. For an 80% confidence level, the middle 80% of the t-distribution curve is shaded, leaving 10% in each of the two tails. The critical value (t*) is where the tails begin, and it defines the cutoff values for the sample data.### AnswerEnter your calculated margin of error in the provided answer box below.(If you are an instructor, consider providing interactive tools or links to t-distribution tables and calculators to facilitate learning.)

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Answered: If n=19, a(x-bar)=31, and s=9, find the…

Math

Statistics

If n=19, a(x-bar)=31, and s=9, find the margin of error at a 80% confidence level Give your answer to two decimal places.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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