If d is the distance between equidistant odd ordinates, the Simpson's rule for the areas, is d/2[h1 + hn x 2(h2 + h4 + ... + hn-1) + 4(h3 O + h5 + ... + hn-2)] [h1 + hn + 2(h3 + h5 + ... + hn-2) + 4(h2 + h4ppp + ... + hn - 1)] d/6 [h1 + hn + 2(h3 + h5+ ... + hn-2) + 4(h2 + h4 + + hn - 1)] *** d/3[h1 + hn + 2(h3 + h5 + ... + hn-2) + 4(h2 + h4 + ... + hn- 1)] O O
If d is the distance between equidistant odd ordinates, the Simpson's rule for the areas, is d/2[h1 + hn x 2(h2 + h4 + ... + hn-1) + 4(h3 O + h5 + ... + hn-2)] [h1 + hn + 2(h3 + h5 + ... + hn-2) + 4(h2 + h4ppp + ... + hn - 1)] d/6 [h1 + hn + 2(h3 + h5+ ... + hn-2) + 4(h2 + h4 + + hn - 1)] *** d/3[h1 + hn + 2(h3 + h5 + ... + hn-2) + 4(h2 + h4 + ... + hn- 1)] O O
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
![If d is the distance between
equidistant odd ordinates, the
Simpson's rule for the areas, is
d/2[h1 + hn x 2(h2 + h4 + ... + hn-1) + 4(h3 O
+ h5 + ... + hn-2)]
[h1 + hn + 2(h3 + h5 + ... + hn-2) + 4(h2 +
h4ppp + ... + hn - 1)]
d/6 [h1 + hn + 2(h3 + h5+ ... + hn-2) + 4(h2
+ h4 + ... + hn- 1)]
d/3[h1 + hn+ 2(h3 + h5 + ... + hn-2) + 4(h2
+ h4+...+ hn- 1)]
O
O](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5be9a9ba-0a4d-4ca2-a167-45fc546a3e4f%2F9f299cc1-7811-4def-a4d5-de89abfb6027%2Fe88ugjy_processed.jpeg&w=3840&q=75)
Transcribed Image Text:If d is the distance between
equidistant odd ordinates, the
Simpson's rule for the areas, is
d/2[h1 + hn x 2(h2 + h4 + ... + hn-1) + 4(h3 O
+ h5 + ... + hn-2)]
[h1 + hn + 2(h3 + h5 + ... + hn-2) + 4(h2 +
h4ppp + ... + hn - 1)]
d/6 [h1 + hn + 2(h3 + h5+ ... + hn-2) + 4(h2
+ h4 + ... + hn- 1)]
d/3[h1 + hn+ 2(h3 + h5 + ... + hn-2) + 4(h2
+ h4+...+ hn- 1)]
O
O
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