Compute the resultant of the concurrent forces shown in N. P1 = 254 N, P2 = 490 N, P3 = 414 N, P4 = 224 N, 01 = 27, 02 = 25, and 03 = 60. Write numerical value only in 2 decimal places. P1 P4 0₂ + Y 0₁ P3 P2 +x

Compute the resultant of the concurrent forces shown in N. P1 = 254 N, P2 = 490 N, P3 = 414 N, P4 = 224 N, 01 = 27, 02 = 25, and 03 = 60. Write numerical value only in 2 decimal places. P1 P4 0₂ + Y 0₁ P3 P2 +x

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Laws of Equilibrium

A body is said to be in equilibrium if the system of forces acting on the body tends to keep the body at rest, in other words, there is no translation motion or net torque on the body. Under such conditions, the equilibrium conditions are to be applied to analyze the condition. The branch of mechanics that deals with this condition is known as 'statics'. Under equilibrium, there are no net forces on the body.

Question

Compute the resultant of the concurrent forces shown in N. P1 = 254 N, P2 = 490 N,
P3 = 414 N, P4 = 224 N, 01 = 27, 02 = 25, and 03 = 60. Write numerical value only
in 2 decimal places.
P1
P4
0₂
+ Y
0₁
P3
P2
+x

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