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ALVIN (FN) = 1+ 12 + 23 + 9 + 14 = 59 NAVALTA (MN) = 14 + 1 + 23 + 1 + 12 +21 +1 = 72 DELIRO (SN) = 4 + 5+ 12 +9 + 19 + 16 = 65 4 m B 4 m Determine the components of F that act along rod AC and perpendicular to it. Point B is located 3 m along the rod from end C. F= SN N 3 m 6 m 4 m D

ALVIN (FN) = 1+ 12 + 23 + 9 + 14 = 59 NAVALTA (MN) = 14 + 1 + 23 + 1 + 12 +21 +1 = 72 DELIRO (SN) = 4 + 5+ 12 +9 + 19 + 16 = 65 4 m B 4 m Determine the components of F that act along rod AC and perpendicular to it. Point B is located 3 m along the rod from end C. F= SN N 3 m 6 m 4 m D

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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EXAMPLE: ALVIN (FN) = 1+ 12 + 23 +9 + 14 = 59 NAVALTA (MN) = 14 +1+ 23 + 1+ 12 + 21 + 1 = 72 DELIRO (SN) = 4 + 5+ 12 + 9 + 19 + 16 = 65 4 m B m 1. Determine the components of F that act along rod AC and perpendicular to it. Point B is located 3 m along the rod from end C. F= SN N 3 m 6 m 4 m 2. Determine the following: a) Magnitude of the projected component of along the line of action of F2 b) Angle 0 between the two cables attached to the pipe. F, = MN Ib 120 60° F, = SN Ib 3. The guy wires are used to support the telephone pole. Represent the force in each wire in Cartesian vector form. Neglect the diameter of the pole 1.5 m F, = MNN F2= EN N 4 m 2 m D. 4 m 3 m.
Transcribed Image Text:EXAMPLE: ALVIN (FN) = 1+ 12 + 23 +9 + 14 = 59 NAVALTA (MN) = 14 +1+ 23 + 1+ 12 + 21 + 1 = 72 DELIRO (SN) = 4 + 5+ 12 + 9 + 19 + 16 = 65 4 m B m 1. Determine the components of F that act along rod AC and perpendicular to it. Point B is located 3 m along the rod from end C. F= SN N 3 m 6 m 4 m 2. Determine the following: a) Magnitude of the projected component of along the line of action of F2 b) Angle 0 between the two cables attached to the pipe. F, = MN Ib 120 60° F, = SN Ib 3. The guy wires are used to support the telephone pole. Represent the force in each wire in Cartesian vector form. Neglect the diameter of the pole 1.5 m F, = MNN F2= EN N 4 m 2 m D. 4 m 3 m.
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