If at -score is calculated to be -2.03 and our critical values are -2.365 and 2.365, what decision do we make about our research study? Reject the null hypothesis Accept the null hypothesis Accept the experimental hypothesis Accept the research hypothesis
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- The summary statistics for a certain set of points are: n= 25, s, = 107.27, E (x-x)´ = 70.93, and b, = 39.37. Use the critical value method to test the null hypothesis H,: B, =0 versus H, : B, >0. Use the a = 0.01 level of significance. Part: 0/ 4 Part 1 of 4 Find the critical value(s). Round the answer to three decimal places. If there is more than one critical value, separate them with commas. Critical value(s):You are conducting a study to see if the proportion of men over 50 who regularly have their prostate examined is significantly less than 0.15. You use a significance level of a =0.02. Ho:p= 0.15 H1:p < 0.15 You obtain a sample of sizen= 504 in which there are 60 successes. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is. O less than (or equal to) a O greater than a This test statistic leads to a decision to... O reject the null O accept the null O fail to reject the null As such, the final conclusion is that.. O There is sufficient evidence to warrant rejection of the claim that the proportion of men oven 50 who regularly have their prostate examined is less than 0.15. There is not sufficient evidence to warrant rejection of the claim that the proportion of men over 50 who regularly have their prostate examined is…Using the P-value method decide if you should reject the null hypothesis or not. In a sample of 81 adults selected randomly from one town, it is found that 8 of them have been exposed to a particular strain of the flu. At the 0.01 level of significance, you wish to test the proportion of all adults in the town that have been exposed to this strain of the flu is 8%
- You are conducting a study to see if the proportion of women over 40 who regularly have mammograms is significantly more than 0.15. You use a significance level of a = 0.01. Но:р — 0.15 H1:p > 0.15 You obtain a sample of size n 137 in which there are 28 successes. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is.. less than (or equal to) a greater than a This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that. O There is sufficient evidence to warrant rejection of the claim that the proportion of women over 40 who regularly have mammograms is more than 0.15. O There is not sufficient evidence to warrant rejection of the claim that the proportion of women over 40 who regularly have mammograms is more than 0.15. The sample data support…Professor Nord stated that the mean score on the final exam from all the years he has been teaching is a 79%. Colby was in his most recent class, and his class’s mean score on the final exam was 82%. Colby decided to run a hypothesis test to determine if the mean score of his class was significantly greater than the mean score of the population. α = .01. What is the mean score of the population? What is the mean score of the sample? Is this test one-tailed or two-tailed? Why?You are conducting a study to see if the proportion of voters who prefer Candidate A is significantly less than 0.52. You use a significance level of a = 0.01. Ho:p = 0.52 H1:p < 0.52 You obtain a sample of size n = 414 in which there are 208 successes. What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... less than (or equal to) a greater than a This p-value leads to a decision to... reject the null accept the null O fail to reject the null
- A local coach wants to see if training in light rooms or dark rooms impacts athlete performance. With the single team, the coach tries training in different conditions and takes measurements. She ran her analysis in Microsoft Excel and received the following output table. If the P value is less than 0.05, the null hypothesis may be rejected. Based on the data table, what decision should the coach make about the hypothesis? Coach should reject the null hypothesis. Coach should fail to reject the null hypothesis. Coach should accept the null hypothesis. Coach does not have enough information to decide.I know the answer between choice I) and choice II) is: I) But why is it choice I)?econometrics
- You are conducting a study to see if the proportion of men over 50 who regularly have their prostate examined is significantly different from 0.45. You use a significance level of α=0.002. H0:p=0.45 H1:p≠0.45You obtain a sample of size n=196 in which there are 81 successes.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = The p-value is... less than (or equal to) αα greater than αα This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the proportion of men over 50 who regularly have their prostate examined is different from 0.45. There is not sufficient evidence to warrant rejection of the claim that the proportion of men over 50 who regularly have their…You are conducting a study to see if the proportion of women over 40 who regularly have mammograms is significantly more than 0.79. You use a significance level of a 0.01. Ho:p = 0.79 H1:p > 0.79 You obtain a sample of size n 253 in which there are 213 successes. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... O less than (or equal to) a O greater than a This test statistic leads to a decision to... O reject the null O accept the null O fail to reject the nullThis is the step1, so step 2 and step 3 must be answered. (Step 2: Test Statistic -Pearson's r correlation coefficient AND Step 3: Critical Values ) so based it from the photo. Show COMPLETE SOLUTIONS. The table shows the number of hours spend by 30 students in studing and their test scores. Solve for the Pearson’s r and interpret the results. Use 5% significance level. Step 1: Null and Alternative Hypothesis Ho: r = 0; There is no significant relationship between the number of hours spent studying and the students test scores. Ha: r ≠ 0; There is a significant relationship between the number of hours spent studying and the students test scores.