RO RS 20 2s 10.0 10s 11.0 11s 120 12s Ferearm (inches) The equation of the line is given by the following regression equation. Predicted height = 39 + 2.7 - forearm length (a) Based on the graph of this line, which is the best prediction of the height of a woman with a forearm of 11 inches? A. 61.5 inches B. 68 inches C. 68.75 inches D. just under 72 inches (b) What is the most precise and accurate interpretation of the slope?

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Concept explainers
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1
Data
Prediction
residual
Squared error Outliers? Sigificance Level
0.05
Linear Regression and Scatt
E^2
-0.31147541 0.097016931
-3.31147541 10.96586939
2.691256831 7.242863328
2 X
Y
Yhat
Regression Line
Y-Intercept
Slope
3
8
5.31147541
a=
14.90710383
16
4
2
5.31147541
b=
-1.199453552
14
3
14
11.30874317
Correlation Coefficient
r=
-0.836787256
12
11
12.50819672
-1.508196721
2.27465735
Correlation of Determination
0.700212911
10
Sample Size
Test statistic
P-value of r
Sum of Squared Error
Standard deviation
0.691256831 0.477836006
1.890710383 3.574785751
7
12
11.30874317
In=
11
8
8
4
12
10.10928962
t=D
-4.584899808
6
11
12.50819672
-1.508196721
2.27465735
P-value
0.001318575
4
10
1
12
13.70765027
-1.707650273 2.916069456
SSE
40.98907104
11
14
14.90710383
-0.907103825
0.82283735
s=
2.134090257
2
12
12
8.909836066
3.090163934 9.549113142
1
3
4
5
13
4
11
10.10928962
0.890710383 0.793364986
14
Explanatory Variable >
15
16
17
18
19
20
21
22
23
24
25.
Linear Regression
response variable y
Transcribed Image Text:1 Data Prediction residual Squared error Outliers? Sigificance Level 0.05 Linear Regression and Scatt E^2 -0.31147541 0.097016931 -3.31147541 10.96586939 2.691256831 7.242863328 2 X Y Yhat Regression Line Y-Intercept Slope 3 8 5.31147541 a= 14.90710383 16 4 2 5.31147541 b= -1.199453552 14 3 14 11.30874317 Correlation Coefficient r= -0.836787256 12 11 12.50819672 -1.508196721 2.27465735 Correlation of Determination 0.700212911 10 Sample Size Test statistic P-value of r Sum of Squared Error Standard deviation 0.691256831 0.477836006 1.890710383 3.574785751 7 12 11.30874317 In= 11 8 8 4 12 10.10928962 t=D -4.584899808 6 11 12.50819672 -1.508196721 2.27465735 P-value 0.001318575 4 10 1 12 13.70765027 -1.707650273 2.916069456 SSE 40.98907104 11 14 14.90710383 -0.907103825 0.82283735 s= 2.134090257 2 12 12 8.909836066 3.090163934 9.549113142 1 3 4 5 13 4 11 10.10928962 0.890710383 0.793364986 14 Explanatory Variable > 15 16 17 18 19 20 21 22 23 24 25. Linear Regression response variable y
5. Best fit line, Regression Line, Least Square Line: We would like to be able to make prediction from
the scatterplot data. One way to do this is create a "best fit line". Then use the line to predict values that
have not been measured yet. Let's label our variables;
a is the erplanatory variable.
y is the response variable.
ŷ is the predicted response variable that we get by using our best fit line.
In general the formula we use in statistics for the best fit line is
ŷ = a + bx
where a and b found from the bivariant data and are constants. In this case b is the rate of change, or slope
of the line and a is the initial value or y-intercept of the line.
Below we have data from 21 college students. Forearm length in inches is the explanatory variable. Height in
inches is the response variable. The line is a good summary of the linear pattern in the data.
74
72
70
68
66
64
62
60
58
56
9.5 10.0 10.5 11.0 11.5 12.O 12.5
Forearm (inches)
8.0 8.5
9.0
The equation of the line is given by the following regression equation.
Predicted height = 39 + 2.7 · forearm length
(a) Based on the graph of this line, which is the best prediction of the height of a woman with a forearm of
11 inches?
A. 64.5 inches B. 68 inches
C. 68.75 inches
D. just under 72 inches
(b) What is the most precise and accurate interpretation of the slope?
(c) Use the equation of the line to predict the height of a woman with a 10-inch forearm. Show your work.
Transcribed Image Text:5. Best fit line, Regression Line, Least Square Line: We would like to be able to make prediction from the scatterplot data. One way to do this is create a "best fit line". Then use the line to predict values that have not been measured yet. Let's label our variables; a is the erplanatory variable. y is the response variable. ŷ is the predicted response variable that we get by using our best fit line. In general the formula we use in statistics for the best fit line is ŷ = a + bx where a and b found from the bivariant data and are constants. In this case b is the rate of change, or slope of the line and a is the initial value or y-intercept of the line. Below we have data from 21 college students. Forearm length in inches is the explanatory variable. Height in inches is the response variable. The line is a good summary of the linear pattern in the data. 74 72 70 68 66 64 62 60 58 56 9.5 10.0 10.5 11.0 11.5 12.O 12.5 Forearm (inches) 8.0 8.5 9.0 The equation of the line is given by the following regression equation. Predicted height = 39 + 2.7 · forearm length (a) Based on the graph of this line, which is the best prediction of the height of a woman with a forearm of 11 inches? A. 64.5 inches B. 68 inches C. 68.75 inches D. just under 72 inches (b) What is the most precise and accurate interpretation of the slope? (c) Use the equation of the line to predict the height of a woman with a 10-inch forearm. Show your work.
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