If an undirected graph has more than two vertices of odd degree, it does not have an Euler path.
If an undirected graph has more than two vertices of odd degree, it does not have an Euler path.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Prove the following theorem of Euler.
If an undirected graph has more than two vertices of odd degree, it does not
have an Euler path.
Hint: Try a proof by contradiction, and model your argument on the proof of Theorem 2.8.

Transcribed Image Text:**Theorem 2.8** If a graph \( G \) has an Euler circuit, then all the vertices of \( G \) have even degree.
**Proof:** Let \( v \) be a vertex in \( G \). If the degree of \( v \) is zero, there is nothing to prove. If the degree of \( v \) is nonzero, then some edges on the Euler circuit touch it, and since the Euler circuit contains all of \( G \)'s edges, the number of touches by these edges equals the degree of \( v \). If we traverse the circuit, starting and ending at \( v \), we must leave \( v \) the same number of times as we return to \( v \). Therefore the number of touches by an edge in the Euler circuit is even.
Euler’s observations about paths have related proofs. These are left as exercises.
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