There is a vertex v in a bipartite graph G=(V,E) with deg(v)=m+n, where m = |V2I. |V₁|,n=
There is a vertex v in a bipartite graph G=(V,E) with deg(v)=m+n, where m = |V2I. |V₁|,n=
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Can you explain the solution a bit more as I am not understanding how you proved it to be false?
Is it false cause degree m+n would imply a vertex in M or N that has edges contained within the subset which breaks definition of bipartite?
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