If 7.3 grams of sodium carbonate are used in the reaction and the result a 74.0% yield, what is the actual yield(grams )of sodium phosphate will be formed? (Molar masses: Na2CO3 = 105.99 g/mol and Na3PO4 = 163.94 g/mol Sn3(PO4)4 + 6 Na2CO3 → 3 Sn(CO3)2 + 4 Na3PO4
If 7.3 grams of sodium carbonate are used in the reaction and the result a 74.0% yield, what is the actual yield(grams )of sodium phosphate will be formed? (Molar masses: Na2CO3 = 105.99 g/mol and Na3PO4 = 163.94 g/mol Sn3(PO4)4 + 6 Na2CO3 → 3 Sn(CO3)2 + 4 Na3PO4
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter4: Stoichiometry
Section: Chapter Questions
Problem 4.24PAE: 4.24 Ammonia gas can be prepared by the reaction CaO(s)+2NH4Cl(s)2NH3(g)+H2O(g)+CaCl2(s) If 112 g of...
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If 7.3 grams of sodium carbonate are used in the reaction and the result a 74.0% yield, what is the actual yield(grams )of sodium phosphate will be formed? (Molar masses: Na2CO3 = 105.99 g/mol and Na3PO4 = 163.94 g/mol
Sn3(PO4)4 + 6 Na2CO3 → 3 Sn(CO3)2 + 4 Na3PO4
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If 7.3 grams of sodium carbonate are used in the reaction and the result a 74.0% yield, what is the actual yield(grams )of sodium phosphate will be formed? (Molar masses: Na2CO3 = 105.99 g/mol and Na3PO4 = 163.94 g/mol
Sn3(PO4)4 + 6 Na2CO3 → 3 Sn(CO3)2 + 4 Na3PO4
note please explain well, I asked this already and it lacks info for me.
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