If 45.3 mL of 0.116 M HC1 solution is needed to neutralize a solution of KOH, how many grams of KOH must be present in the solution? ? m = Submit Request Answer
If 45.3 mL of 0.116 M HC1 solution is needed to neutralize a solution of KOH, how many grams of KOH must be present in the solution? ? m = Submit Request Answer
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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b Answered: zinc metal is added to X
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A openvellum.ecollege.com/course.html?courseld=16418591&OpenVellumHMAC=013628d899c889f48948ece53ef3ebff#10001
First, write the balanced equation for the reaction.
Scores
AGNO3 (aq) + KCI(aq) → AgCl(s) + KNO3(aq)
Pearson eText
Next, calculate the moles of the known substance, KCI, by dividing the given mass, after converting from mg to g (1000 mg =1g), by its molar mass, 74.55 g/m
multiply by the mole ratio from the balanced equation, 1:1, to convert from mol KCl to mol AGNO3. Finally, convert mol AgNO3 to M AgN03 using its given vo
converting from mL to L (1000 mL =1L).
Study Area
1 mot KÇI
1000 nL
Molarity of AgNO3 = 0.765 mg KCI ×
1 mol AgNO3
1 motKCI
Document Sharing
= 3.86 x 10
1000 ng
74.55 KCI
26.6 mL AGNO3
1L
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If 45.3 mL of 0.116 M HCl solution is needed to neutralize a solution of KOH, how many grams of KOH must be present in the solution?
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