Limiting reagents To establish the limiting reagent, we will calculate the number of moles of HCI(aq) and the number of moles of NaOH(aq) based on the run composition described in Table 1. mol Molarity (M) = mol = Mx L (8) Liters (L) 131 Table 1: Run compositions RUN NUMBER ml of water ml of 0.50 M HCI ml of 1.00 M NAOH Run 1 2.00 2.00 1.00 Run 2 1.00 3.00 1.00 Run 3 0.00 4.00 1.00 Run 4 2.00 1.00 2.00

Limiting reagents To establish the limiting reagent, we will calculate the number of moles of HCI(aq) and the number of moles of NaOH(aq) based on the run composition described in Table 1. mol Molarity (M) = mol = Mx L (8) Liters (L) 131 Table 1: Run compositions RUN NUMBER ml of water ml of 0.50 M HCI ml of 1.00 M NAOH Run 1 2.00 2.00 1.00 Run 2 1.00 3.00 1.00 Run 3 0.00 4.00 1.00 Run 4 2.00 1.00 2.00

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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