Limiting reagents To establish the limiting reagent, we will calculate the number of moles of HCI(aq) and the number of moles of NaOH(aq) based on the run composition described in Table 1. mol Molarity (M) = mol = Mx L (8) Liters (L) 131 Table 1: Run compositions RUN NUMBER ml of water ml of 0.50 M HCI ml of 1.00 M NAOH Run 1 2.00 2.00 1.00 Run 2 1.00 3.00 1.00 Run 3 0.00 4.00 1.00 Run 4 2.00 1.00 2.00

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Limiting reagents
To establish the limiting reagent, we will calculate the number of moles of HCI(aq) and the
number of moles of NaOH(aq) based on the run composition described in Table 1.
mol
Molarity (M)=
mol = M x L
(8)
Liters (L)
131
Table 1: Run compositions
RUN NUMBER
ml of water
ml of 0.50 M HCI
ml of 1.00 M NAOH
Run 1
2.00
2.00
1.00
Run 2
1.00
3.00
1.00
Run 3
0.00
4.00
1.00
Run 4
2.00
1.00
2.00
Transcribed Image Text:Limiting reagents To establish the limiting reagent, we will calculate the number of moles of HCI(aq) and the number of moles of NaOH(aq) based on the run composition described in Table 1. mol Molarity (M)= mol = M x L (8) Liters (L) 131 Table 1: Run compositions RUN NUMBER ml of water ml of 0.50 M HCI ml of 1.00 M NAOH Run 1 2.00 2.00 1.00 Run 2 1.00 3.00 1.00 Run 3 0.00 4.00 1.00 Run 4 2.00 1.00 2.00
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