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How many milliliters of solution of 0.150 M LE-COs could a student make from 8.33 grams of Li.CO, and excess water? 8.33 ADD FACTOR x( ) 1.33 0.01 H 18.02 DELETE 0.752 1000 1 ANSWER 0.150 73.89 mol Li:CO: L solution M Li:CO: g Li:CO 0.001 752 RESET 5 100 mL solution 10 0.1

How many milliliters of solution of 0.150 M LE-COs could a student make from 8.33 grams of Li.CO, and excess water? 8.33 ADD FACTOR x( ) 1.33 0.01 H 18.02 DELETE 0.752 1000 1 ANSWER 0.150 73.89 mol Li:CO: L solution M Li:CO: g Li:CO 0.001 752 RESET 5 100 mL solution 10 0.1

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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STARTING AMOUNT X How many milliliters of solution of 0.150 M LE-COs could a student make from 8.33 grams of Li:CO, and excess water? 8.33 ADD FACTOR x( ) 1.33 0.01 18.02 0.752 DELETE A 1000 1 ANSWER 0.150 73.89 0.001 752 RESET 5 100 10 mol Li:CO: L solution M Li:CO: g Li:CO: mL solution 0.1
Transcribed Image Text:STARTING AMOUNT X How many milliliters of solution of 0.150 M LE-COs could a student make from 8.33 grams of Li:CO, and excess water? 8.33 ADD FACTOR x( ) 1.33 0.01 18.02 0.752 DELETE A 1000 1 ANSWER 0.150 73.89 0.001 752 RESET 5 100 10 mol Li:CO: L solution M Li:CO: g Li:CO: mL solution 0.1
Expert Solution
Step 1

Given = 

concentration = 0.150 M 

Wt . In gm = 8.33 g 

Molecular wt = 73.89 =74 g/mol

73.88 g of Li2Co3 (lithium carbonate ) when dissolved in 1L of water we will get 1M solution . 

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