If 4.27 grams of sucrose, C12H22O11, are dissolved in 15.2 grams of water, what will be the boiling point of the resulting solution? (ΔTb= Kb ×molality;  Kb for water = 0.512 oC/m)   ΔTb = Answer (Answer to 2 dp) Boiling point =Answer........... oC (Answer to 2 dp)

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