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Identify two (2) unwanted sources of heat loss and/or gain that may have contributed to the error in the experiment. Elaborate.

Identify two (2) unwanted sources of heat loss and/or gain that may have contributed to the error in the experiment. Elaborate.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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1:13 0 * ll 66%i Cyra Garces Active Now CALORIMETRY HEAT OF FUSION Trial 1 Trial 2 Mass of ice M (grams) 79 79 Mass of warm water Mter (grams) 120 119 Initial temperature of water Tinitial ("C) 41 42 Final temperature of mixture Tfinal ("C) -4 Calculated heat of fusion of ice Leperinemtal (cal/g) 72.4 60.8 Standard value of heat of fusion of ice Lemdard (cal/g) 79.7 79.7 Percentage error 9.22% 23.76% Calculations According to the principle of the conservation of energy, the quantity of heat absorbed by the ice as it melts (Quained melring) and then heats up to the final equilibrium temperature (Qpain by melted ice) must equal the quantity of heat released by the warm water (Qlast by warm water) as it cools down to the final equilibrium temperature. Mathematically: le guined metingl iast by warm water pained meltingl + o cat (M(L) + (M)(1)T - OC) = (Mt(1)(Tie- T fina - 0C) - (Mt(1 final water initial More Edit II -
Transcribed Image Text:1:13 0 * ll 66%i Cyra Garces Active Now CALORIMETRY HEAT OF FUSION Trial 1 Trial 2 Mass of ice M (grams) 79 79 Mass of warm water Mter (grams) 120 119 Initial temperature of water Tinitial ("C) 41 42 Final temperature of mixture Tfinal ("C) -4 Calculated heat of fusion of ice Leperinemtal (cal/g) 72.4 60.8 Standard value of heat of fusion of ice Lemdard (cal/g) 79.7 79.7 Percentage error 9.22% 23.76% Calculations According to the principle of the conservation of energy, the quantity of heat absorbed by the ice as it melts (Quained melring) and then heats up to the final equilibrium temperature (Qpain by melted ice) must equal the quantity of heat released by the warm water (Qlast by warm water) as it cools down to the final equilibrium temperature. Mathematically: le guined metingl iast by warm water pained meltingl + o cat (M(L) + (M)(1)T - OC) = (Mt(1)(Tie- T fina - 0C) - (Mt(1 final water initial More Edit II -
2. Identify two (2) unwanted sources of heat loss and/or gain that may have contributed to the error in the experiment. Elaborate.
Transcribed Image Text:2. Identify two (2) unwanted sources of heat loss and/or gain that may have contributed to the error in the experiment. Elaborate.
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