**Question 6**Identify the correct relationship between the output voltage and two voltage sources at the input of an ideal op-amp circuit.**Circuit Diagram:**The image depicts an ideal operational amplifier circuit (Fig. 3) with the following components and connections:- Two input voltages: $ v_{1s} $ and $ v_{2s} $.- Two 1 kΩ resistors connected to inputs $ v_{1s} $ and $ v_{2s} $.- A 2 kΩ resistor connected to the inverting input.- Feedback loop with a 2 kΩ resistor connected from the output $ v_0 $ to the inverting input.**Options:**a) $ v_0(t) = v_{2s}(t) - 2v_{1s}(t) $b) $ v_0(t) = 2(v_{2s}(t) - v_{1s}(t)) $c) $ v_0(t) = 0.5(v_{1s}(t) - v_{2s}(t)) $d) $ v_0(t) = \left(\frac{2}{3}v_{2s}(t) - 2v_{1s}(t)\right) $- ○ a) a- ○ b) b- ○ c) c- ○ d) d**Explanation of the Circuit:**This is a differential amplifier circuit using an operational amplifier with feedback to control the output voltage. This type of circuit amplifies the difference between two input voltages, $ v_{1s} $ and $ v_{2s} $. The resistor values set the gain of the amplifier, influencing the output voltage $ v_0 $ in relation to the input voltages.

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Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Step 1: Key Assumptions and Virtual Ground Concept

Before diving into calculations, it's important to note the assumptions made for ideal op-amps:

No current flows into the op-amp input terminals.
The voltage difference between the inverting (-) and non-inverting (+) inputs is zero.

Given our assumptions for ideal op-amps, the voltage at the inverting (-) terminal is the same as the non-inverting (+) terminal. Thus, the voltage at the inverting terminal is $Error converting from MathML to accessible text.$ because the non-inverting terminal is grounded through a voltage source.

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