Ideally speaking, bonds tend to form between two particles such that they are separated by a distance where net force is exerted on them, and their Select answer from the options below overall energy is
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A: Mass of bullet (mb)=7.8 g Initial speed of the bullet (u)=690 m/s Penetration in trunk (d)=6.2 cm
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A: Solution:-Given thatmass of box(m)=32.5 kgdisplacement (s)=4.75 mConstant applied force (F)=145…
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A: thank you
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A: The above problem can be saved by using the concept of photoelectric effect as follows
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A: mass of ice flake = 2.12 gradius (r) = 16.2 cm = 0.162 m surface type = frictionless
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A: Since you have posted a question with multiple sub-parts, we will solve the first three sub-parts…
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A: Given: mass, m = 0.171 kg initial velocity, u = 5.95 m/s final velocity, v = 2.35 m/s
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Q: O Ug → Eth ○ Ug → K + Eth OK → Eth not enough information OK-Ug O Ug → K
A: at the top of side you have potential energyat the bottomyou have kinetic energy
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A: To answer this question we have to be aware of dot product and magnitude formula
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A: Mass of the object m=0.4 g so force applied by the weight of the object F=mg=0.4*9.8*10-3=3.92*10-3N…
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A: a) The required kinetic energy is, b) The required total mechanical energy is,
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A: As per our guidlines we are supposed to answer only one question. kindly respond other questions as…
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A: v1=34m/s v2=27m/s We need to find The ratio of the amount of kinetic energy converted to internal…
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A: thank you
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- A hockey puck with a mass of 0.159 kg slides over the ice. The puck initially slides with a speed of 6.15 m/s, but it comes to a rough patch in the ice which slows it down to a speed of 3.15 m/s. How much energy is dissipated as the puck slides over the rough patch?At which point are the atoms forced so close together that the repulsive potential energy is greater than the attractive potential energy? Question 1 options: 5 1 3A 35.5 kg box initially at rest is pushed 5.75 m along a rough, horizontal floor with a constant applied horizontal force of 130 N. If the coefficient of friction between box and floor is 0.300, find the following. (a) the work done by the applied force (b) the increase in internal energy in the box-floor system due to friction (c) the work done by the normal force (d) the work done by the gravitational force (e) the change in kinetic energy of the box (f) the final speed of the box m/s
- A 36.0 kg box initially at rest is pushed 5.45 m along a rough, horizontal floor with a constant applied horizontal force of 150 N. If the coefficient of friction between box and floor is 0.300, find the following. (a) the work done by the applied force (b) the increase in internal energy in the box-floor system due to friction (c) the work done by the normal force (d) the work done by the gravitational force (e) the change in kinetic energy of the box (f) the final speed of the box m/sA 150-g particle on the inside of a smooth hemispherical bowl of radius R 35.0 cm (see the figure below) is released from point A at rest. Its speed at B is 1,10 m/s. (a) What is its kinetic esergy at B? T h (b) How much mechanical energy is lost as a result of friction as the particle goes from A to B2 (c) Is it possible to determine u from these results in a simple manner? O Yes O No Explain. ..Judy has started fast walking for half an hour each day in an effort to lose weight. Judy currently weighs 100 kg. She walks expending about 0.1 kcal per kg of body weight per minute. For a woman, we multiply the body weight in kg by 0.9 kcal/kg body weight/hour to calculate her BMR. What is Judy’s daily energy expenditure? (Ignore TEF due to its small portion)?
- A 7.80-g bullet moving at 560 m/s penetrates a tree trunk to a depth of 5.80 cm. (a) Use work and energy considerations to find the average frictional force that stops the bullet. (b) Assuming the frictional force is constant, determine how much time elapses between the moment the bullet enters the tree and the moment it stops moving.A force of 30 N acts on an object with mass 5kg, and the object is displaced 10 m along a rough surface. The coefficient of kinetic friction between the object and the surface is 0.35. Calculate the work done by friction.need help to figure this one out
- Which describes a particle that is located on a curved "hilltop" of a potential energy curve? O It is in stable equilibrium. O It is in unstable equilibrium. O It is in neutral equilibrium: eTextbook and Media Save for Later AttemptA 7.80-g bullet moving at 650 m/s penetrates a tree trunk to a depth of 5.80 cm. (a) Use work and energy considerations to find the average frictional force that stops the bullet. (Enter the magnitude.) N (b) Assuming the frictional force is constant, determine how much time elapses between the moment the bullet enters the tree and the moment it stops moving.In the figure, a 3.97 g ice flake is released from the edge of a hemispherical bowl whose radius ris 13.7 cm. The flake-bowl contact is frictionless. (a) How much work is done on the flake by the gravitational force during the flake's descent to the bottom of the bowl? (b) What is the change in the potential energy of the flake-Earth system during that descent? (c) If that potential energy is taken to be zero at the bottom of the bowl, what is its value when the flake is released? (d) If, instead, the potential energy is taken to be zero at the release point, what is its value when the flake reaches the bottom of the bowl? (a) Number (b) Number -5.34e-3 (c) Number 5.34e-3 (d) Number 5.34e-3 Units Units Units Ice flake- Mik Units J