Ice at 0 °C is placed in a Styrofoam cup containing 0.62 kg of lemonade at 32 °C. The specific heat capacity of lemonade is virtually the same as that of water; that is, c = 4180 J/(kg Cº). After the ice and lemonade reach an equilibrium temperature, some ice still remains. The latent heat of fusion for water is Lf = 3.35 x 105 J/ kg. Assume that the mass of the cup is so small that it absorbs a negligible amount of heat, and ignore any heat lost to the surroundings. Determine the mass of ice that has melted, in grams.

College Physics
11th Edition
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Chapter1: Units, Trigonometry. And Vectors
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Ice at 0 °C is placed in a Styrofoam cup
containing 0.62 kg of lemonade at 32 °C. The
specific heat capacity of lemonade is virtually
the same as that of water; that is, c = 4180
J/(kg C°). After the ice and lemonade reach
an equilibrium temperature, some ice still
remains. The latent heat of fusion for water is
Lf = 3.35 x 105 J/ kg. Assume that the mass
of the cup is so small that it absorbs a
negligible amount of heat, and ignore any
heat lost to the surroundings. Determine the
mass of ice that has melted, in grams.
Transcribed Image Text:Ice at 0 °C is placed in a Styrofoam cup containing 0.62 kg of lemonade at 32 °C. The specific heat capacity of lemonade is virtually the same as that of water; that is, c = 4180 J/(kg C°). After the ice and lemonade reach an equilibrium temperature, some ice still remains. The latent heat of fusion for water is Lf = 3.35 x 105 J/ kg. Assume that the mass of the cup is so small that it absorbs a negligible amount of heat, and ignore any heat lost to the surroundings. Determine the mass of ice that has melted, in grams.
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