I. PURPOSE: Is calkutate thr Specitic charge8 Coper Tas waich is the amant of dhange curriedd bya ScopperIaNs, mit II. DATA AND DATA ANALYSIS: Enter your data of the masses, m, and m,2 in kg as related to the current, I, in Ampere and time, t, in minutes in Table (10.1) below: 1. 7. Table(10.1) m1 Current(I) | Time (t) Amount of charge m2 Deposited mass il gai Mcu = (m2-m,) (Kg) (It) %3D (A) (min) (Kg) (Kg) (Coulomb) 06A 0.8 20 10 36. 36.86| 36-67- 36.56 5.19 36.42-36bx D.2 x10 x 60 = "0 7.01/0.01- 0.3A 20 DSx Sxb= 20| 36,88 3る、92 3. D. 06 0,3Á 10 04xるx0= 240 36.92 3.96"| 36 014 Oo 02 Use the data in Table (10.1) to plot the amount of charge (It) versus the mass of the deposited copper Mcu . 2. 3. What type of relationship do you see between Meu and It? DirectLiser 108 Me

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Use the data in Table (10.1) to plot the amount of charge (It) versus the mass of the deposited copper Mcu.

I. PURPOSE:
Is cakutate Hr Specifir charge8coper Taas ubick
is the amant of chage curlied bup mit mo6sScopperIous.
II. DATA AND DATA ANALYSIS:
Enter your data of the masses, m, and m2 in kg as related to the current, I,
in Ampere and time, t, in minutes in Table (10.1) below:
1.
7.
Table(10.1)
Current(I) | Time (t) Amount of charge
Deposited mass
m2
ighlabiai Mcu (m2-m,)
(Kg).
m1
(It)
(A)
(min)
(Kg)
(Kg)
(Coulomb)
0,6A
0.8
20
10
36. 36.86| 36-51- 36.56
7.01/001-
36.82 36.92
D.2 x10 x 60 = 0
A5.49
0.3A
20
D,9X 5x60= 2+D
8.
D. 06
36.92
0,3A
014
10
94X6x 0= 240
36.16 36 6-3698=
05 02
Use the data in Table (10.1) to plot the amount of charge (It) versus the
mass of the deposited copper Mcu.
3.
What type of relationship do you see between Mcu and It?
Direct Liser
108
Transcribed Image Text:I. PURPOSE: Is cakutate Hr Specifir charge8coper Taas ubick is the amant of chage curlied bup mit mo6sScopperIous. II. DATA AND DATA ANALYSIS: Enter your data of the masses, m, and m2 in kg as related to the current, I, in Ampere and time, t, in minutes in Table (10.1) below: 1. 7. Table(10.1) Current(I) | Time (t) Amount of charge Deposited mass m2 ighlabiai Mcu (m2-m,) (Kg). m1 (It) (A) (min) (Kg) (Kg) (Coulomb) 0,6A 0.8 20 10 36. 36.86| 36-51- 36.56 7.01/001- 36.82 36.92 D.2 x10 x 60 = 0 A5.49 0.3A 20 D,9X 5x60= 2+D 8. D. 06 36.92 0,3A 014 10 94X6x 0= 240 36.16 36 6-3698= 05 02 Use the data in Table (10.1) to plot the amount of charge (It) versus the mass of the deposited copper Mcu. 3. What type of relationship do you see between Mcu and It? Direct Liser 108
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