What is the Major product for each of the following reactions? ### Reaction Schemes for Alkyl Halides with Strong Bases#### i.) Alkyl Halide Reaction with Sodium Methoxide (NaOMe)- **Structure:** A cyclohexane ring is bonded to a two-carbon chain with a bromine atom at the end of the chain. The two carbon atoms in the chain are depicted as having wedges indicating stereo centers.- **Reagent:** NaOMe (Sodium Methoxide) This reaction will typically lead to a substitution or elimination process, given the strong base NaOMe, likely resulting in the formation of an alkene through E2 elimination.#### j.) Alkyl Halide Reaction with Sodium Ethoxide (NaOEt)- **Structure:** A cyclohexane ring with a bromine atom attached to one of the ring carbons, also shown with stereochemistry using wedges.- **Reagent:** NaOEt (Sodium Ethoxide)Similar to the first reaction, the use of NaOEt, another strong base, suggests that the reaction might proceed through an elimination mechanism, possibly forming an alkene.#### k.) Alkyl Halide Reaction with Sodium Hydroxide (NaOH)- **Structure:** A cyclohexane ring connected to a three-carbon chain, with a bromine atom near the end, depicted with stereochemistry using a wedge.- **Reagent:** NaOH (Sodium Hydroxide)Given that NaOH is a strong base, it's likely that this reaction will proceed through elimination (E2 mechanism), converting the alkyl halide into an alkene.### Diagram ExplanationEach reaction scheme shows a starting cycloalkane structure with a halide leaving group, followed by a strong base reagent. These reactions are centered on the concept of nucleophilic substitution and elimination in organic chemistry. The stereochemistry, indicated by wedges, is crucial in predicting the product stereochemistry. These diagrams illustrate how strong bases can induce transformations leading to more stable alkene products via elimination.

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Answered: i.) j.) k.) Br Br Br NaOH NaOMe NaOEt

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i.) j.) k.) Br Br Br NaOH NaOMe NaOEt

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

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Question

What is the Major product for each of the following reactions?

### Reaction Schemes for Alkyl Halides with Strong Bases

#### i.) Alkyl Halide Reaction with Sodium Methoxide (NaOMe)
- **Structure:** A cyclohexane ring is bonded to a two-carbon chain with a bromine atom at the end of the chain. The two carbon atoms in the chain are depicted as having wedges indicating stereo centers.
- **Reagent:** NaOMe (Sodium Methoxide)

This reaction will typically lead to a substitution or elimination process, given the strong base NaOMe, likely resulting in the formation of an alkene through E2 elimination.

#### j.) Alkyl Halide Reaction with Sodium Ethoxide (NaOEt)
- **Structure:** A cyclohexane ring with a bromine atom attached to one of the ring carbons, also shown with stereochemistry using wedges.
- **Reagent:** NaOEt (Sodium Ethoxide)

Similar to the first reaction, the use of NaOEt, another strong base, suggests that the reaction might proceed through an elimination mechanism, possibly forming an alkene.

#### k.) Alkyl Halide Reaction with Sodium Hydroxide (NaOH)
- **Structure:** A cyclohexane ring connected to a three-carbon chain, with a bromine atom near the end, depicted with stereochemistry using a wedge.
- **Reagent:** NaOH (Sodium Hydroxide)

Given that NaOH is a strong base, it's likely that this reaction will proceed through elimination (E2 mechanism), converting the alkyl halide into an alkene.

### Diagram Explanation
Each reaction scheme shows a starting cycloalkane structure with a halide leaving group, followed by a strong base reagent. These reactions are centered on the concept of nucleophilic substitution and elimination in organic chemistry. The stereochemistry, indicated by wedges, is crucial in predicting the product stereochemistry. These diagrams illustrate how strong bases can induce transformations leading to more stable alkene products via elimination.

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