Hi,I solved this problem however I am stuck on the last part of it and I am not sure if the book is wrong with the result or if I am having the correct one. I should have a negative Fa force instead I get the same numerical number but positive. Any clue of why? Mathematical RepresentationAppey general equation of equilibrium+5 EM=0+ ε = 0 +¹1 € Fy=0+We Take moment about A+5€ H₂₁₂=0By7+ (By · 3m) - (Mg⋅ 3.5) - (1₁·5m) + (E-6m) (15 · 8) =-61 (3,5tg - 5F₁ + 6Ę −85)= 1 (6857N+15000N- 12000N +800N)3= +5952N = 5952 N † ~ 5.96 KN ↑directionAppey Equil. in+1EF=0-4=-Ay +By-Mg - F2 + √2₂-3₂ = 0-Ay = = By + Mg + F₂ = √₂ + √₂Aq = By - Mg = F₁ +F₂-F35952N - 1962N-3000 + 2000N-1000N=+1990 N = 1990 N $ ~ 1.99 KNwhy is the positive?shouldn't be thisNegative?Helix10 20 30 0 0 2. A uniform 9 metre beam has a mass of 200 kg and is loaded inthe vertically by the parallel forces shown. Calculate thereactions at the roller supports A and B.(Answer: FA = 1.99 KNFB = 5.96 kN)mm3 kN↓11 m.1 kN2 KNm

The value of reaction at A is coming to be positive because you have already assumed the direction…

Answered: 2. A uniform 9 metre beam has a mass of…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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Hi,

I solved this problem however I am stuck on the last part of it and I am not sure if the book is wrong with the result or if I am having the correct one. I should have a negative Fa force instead I get the same numerical number but positive. Any clue of why?

Mathematical Representation
Appey general equation of equilibrium
+5 EM=0
+ ε = 0 +¹1 € Fy=0
+
We Take moment about A
+5€ H₂₁₂=0
By
7
+ (By · 3m) - (Mg⋅ 3.5) - (1₁·5m) + (E-6m) (15 · 8) =
-
6
1 (3,5tg - 5F₁ + 6Ę −85)
= 1 (6857N+15000N- 12000N +800N)
3
= +5952N = 5952 N † ~ 5.96 KN ↑
direction
Appey Equil. in
+1EF=0
-4=
-Ay +By-Mg - F2 + √2₂-3₂ = 0
-Ay = = By + Mg + F₂ = √₂ + √₂
Aq = By - Mg = F₁ +F₂-F3
5952N - 1962N-3000 + 2000N-1000N
=+1990 N = 1990 N $ ~ 1.99 KN
why is the positive?
shouldn't be this
Negative?
Helix
10 20 30 0 0

2. A uniform 9 metre beam has a mass of 200 kg and is loaded in
the vertically by the parallel forces shown. Calculate the
reactions at the roller supports A and B.
(Answer: FA = 1.99 KN
FB = 5.96 kN)
m
m
3 kN
↓
11 m.
1 kN
2 KN
m

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I understand what you say, however, shouldn't the formula confirm the direction I assumed in the first place is correct or incorrect? For the force acting on B, I assumed the force was positive and indeed I had a positive numerical value. So, I still don't understand why I get a positive one acting on A if my first assumption what that the force is negative. Could you please evaluate this as I want to make sure I understood the concept.

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