I Review | Coi An object is undergoing SHM with period 0.265 s and amplitude 6.00 cm. At t = 0 the object is instantaneously at rest at x = 6.00 cm. Part A Calculate the time it takes the object to go from x = 6.00 cm to x = -1.40 cm. Express your answer with the appropriate units. µA 圖]? t = Value Units
I Review | Coi An object is undergoing SHM with period 0.265 s and amplitude 6.00 cm. At t = 0 the object is instantaneously at rest at x = 6.00 cm. Part A Calculate the time it takes the object to go from x = 6.00 cm to x = -1.40 cm. Express your answer with the appropriate units. µA 圖]? t = Value Units
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![### Transcription for Educational Website
**Simple Harmonic Motion Problem**
Consider an object undergoing Simple Harmonic Motion (SHM) with the following properties:
- **Period**: 0.265 seconds
- **Amplitude**: 6.00 centimeters
At time \( t = 0 \), the object is at rest at position \( x = 6.00 \) cm.
**Problem Statement: Part A**
Calculate the time it takes for the object to travel from \( x = 6.00 \) cm to \( x = -1.40 \) cm.
*Instructions:*
- Express your answer with the appropriate units.
You are provided with an input box where you can enter your calculated value and select the unit for your answer.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2e0c671f-6d07-45cf-8505-b36fe395c45a%2F7f412a9c-5b43-4d0e-8827-c7155dc5f580%2Fr0oia8q_processed.png&w=3840&q=75)
Transcribed Image Text:### Transcription for Educational Website
**Simple Harmonic Motion Problem**
Consider an object undergoing Simple Harmonic Motion (SHM) with the following properties:
- **Period**: 0.265 seconds
- **Amplitude**: 6.00 centimeters
At time \( t = 0 \), the object is at rest at position \( x = 6.00 \) cm.
**Problem Statement: Part A**
Calculate the time it takes for the object to travel from \( x = 6.00 \) cm to \( x = -1.40 \) cm.
*Instructions:*
- Express your answer with the appropriate units.
You are provided with an input box where you can enter your calculated value and select the unit for your answer.
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