I Review | Coi An object is undergoing SHM with period 0.265 s and amplitude 6.00 cm. At t = 0 the object is instantaneously at rest at x = 6.00 cm. Part A Calculate the time it takes the object to go from x = 6.00 cm to x = -1.40 cm. Express your answer with the appropriate units. µA 圖]? t = Value Units

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### Transcription for Educational Website

**Simple Harmonic Motion Problem**

Consider an object undergoing Simple Harmonic Motion (SHM) with the following properties:
- **Period**: 0.265 seconds
- **Amplitude**: 6.00 centimeters

At time \( t = 0 \), the object is at rest at position \( x = 6.00 \) cm.

**Problem Statement: Part A**

Calculate the time it takes for the object to travel from \( x = 6.00 \) cm to \( x = -1.40 \) cm.

*Instructions:*
- Express your answer with the appropriate units.

You are provided with an input box where you can enter your calculated value and select the unit for your answer.
Transcribed Image Text:### Transcription for Educational Website **Simple Harmonic Motion Problem** Consider an object undergoing Simple Harmonic Motion (SHM) with the following properties: - **Period**: 0.265 seconds - **Amplitude**: 6.00 centimeters At time \( t = 0 \), the object is at rest at position \( x = 6.00 \) cm. **Problem Statement: Part A** Calculate the time it takes for the object to travel from \( x = 6.00 \) cm to \( x = -1.40 \) cm. *Instructions:* - Express your answer with the appropriate units. You are provided with an input box where you can enter your calculated value and select the unit for your answer.
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