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I Review I Constants A circular conducting ring with radius ro = 0.0420 m lies in the xy-plane in a region of uniform magnetic field B = Bo[1 – 3(t/to)² + 2(t/to)³]k. In this expression, Correct answer is shown. Your answer 0.065 V was either rounded differently or used a different number of significant figures than required for this part. to = 0.0100 s and is constant, t is time, k is the unit vector in the +z-direction, and Bo = 0.0800 T is constant. At points a and b (see the figure (Figure 1)) there is a small gap in the ring with wires leading to an external circuit of resistance R = 12.0 N. There is no magnetic field at the location of the external circuit. Part C Determine the polarity of the emf in the ring at time t = 5.00 x 10-3 s. O clockwise O counterclockwise Submit Request Answer Part D Figure 1 of 1 Because of the internal resistance of the ring, the current through R at the time given in part B is only 3.00 mA. Determine the internal resistance of the ring. Express your answer in ohms. Hνα ΑΣφ ? Ω [b Submit Previous Answers Request Answer 12.0N X Incorrect; Try Again; 3 attempts remaining

I Review I Constants A circular conducting ring with radius ro = 0.0420 m lies in the xy-plane in a region of uniform magnetic field B = Bo[1 – 3(t/to)² + 2(t/to)³]k. In this expression, Correct answer is shown. Your answer 0.065 V was either rounded differently or used a different number of significant figures than required for this part. to = 0.0100 s and is constant, t is time, k is the unit vector in the +z-direction, and Bo = 0.0800 T is constant. At points a and b (see the figure (Figure 1)) there is a small gap in the ring with wires leading to an external circuit of resistance R = 12.0 N. There is no magnetic field at the location of the external circuit. Part C Determine the polarity of the emf in the ring at time t = 5.00 x 10-3 s. O clockwise O counterclockwise Submit Request Answer Part D Figure 1 of 1 Because of the internal resistance of the ring, the current through R at the time given in part B is only 3.00 mA. Determine the internal resistance of the ring. Express your answer in ohms. Hνα ΑΣφ ? Ω [b Submit Previous Answers Request Answer 12.0N X Incorrect; Try Again; 3 attempts remaining

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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I Review I Constants - 0.0420 m A circular conducting ring with radius ro = lies in the xy-plane in a region of uniform magnetic field B = Bo[1 – 3(t/to)² + 2(t/to)*]k. In this expression, Correct answer is shown. Your answer 0.065 V was either rounded differently or used a different number of significant figures than required for this part. 0.0100 s and is constant, t is time, k is the unit to vector in the +z-direction, and Bo = 0.0800 T is constant. At points a and b (see the figure (Figure 1)) there is a small gap in the ring with wires leading to an external circuit of resistance R = 12.0 S. There is no Part C magnetic field at the location of the external circuit. Determine the polarity of the emf in the ring at time t = 5.00 × 10¬³ s. clockwise counterclockwise Submit Request Answer Part D Figure 1 of 1 Because of the internal resistance of the ring, the current through R at the time given in part B is only 3.00 mA. Determine the internal resistance of the ring. Express your answer in ohms. ? r = Ω Submit Previous Answers Request Answer X- 12.0 N X Incorrect; Try Again; 3 attempts remaining
Transcribed Image Text:I Review I Constants - 0.0420 m A circular conducting ring with radius ro = lies in the xy-plane in a region of uniform magnetic field B = Bo[1 – 3(t/to)² + 2(t/to)*]k. In this expression, Correct answer is shown. Your answer 0.065 V was either rounded differently or used a different number of significant figures than required for this part. 0.0100 s and is constant, t is time, k is the unit to vector in the +z-direction, and Bo = 0.0800 T is constant. At points a and b (see the figure (Figure 1)) there is a small gap in the ring with wires leading to an external circuit of resistance R = 12.0 S. There is no Part C magnetic field at the location of the external circuit. Determine the polarity of the emf in the ring at time t = 5.00 × 10¬³ s. clockwise counterclockwise Submit Request Answer Part D Figure 1 of 1 Because of the internal resistance of the ring, the current through R at the time given in part B is only 3.00 mA. Determine the internal resistance of the ring. Express your answer in ohms. ? r = Ω Submit Previous Answers Request Answer X- 12.0 N X Incorrect; Try Again; 3 attempts remaining
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