I Review Determine the normal stress developed at corner A of the column. Take P = 280 kN and P, = 480 kN . (Figure 1) Express your answer to three significant figures and include the appropriate units. Enter negative value in the case of compression and positive in the case of tension. Value Units igure < 1 of 1 > Submit Request Answer 100 mm 100 mm Part B 50 mm 100 mm 150 mm Determine the normal stress developed at corner B of the column. Take that P = 280 kN and P = 480 kN. 150 mm B 150 mm 150 mm Express your answer to three significant figures and include the appropriate units. Enter negative value in the case of compression and positive in the case of tension. HA Value Units

I Review Determine the normal stress developed at corner A of the column. Take P = 280 kN and P, = 480 kN . (Figure 1) Express your answer to three significant figures and include the appropriate units. Enter negative value in the case of compression and positive in the case of tension. Value Units igure < 1 of 1 > Submit Request Answer 100 mm 100 mm Part B 50 mm 100 mm 150 mm Determine the normal stress developed at corner B of the column. Take that P = 280 kN and P = 480 kN. 150 mm B 150 mm 150 mm Express your answer to three significant figures and include the appropriate units. Enter negative value in the case of compression and positive in the case of tension. HA Value Units

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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a=2.1m (1) c = 2m b = 3.1m d = 1.8m P = 80 kN WHAT IS THE AXIAL STRESS IN ROD 1 ? ANSWER IN MPa ROUNDED-OFF TO 2 DECIMAL PLACES B dia. of rod 1: = 13mm dia of rod 2 = 11 mm
Note that : σ2= 14 σ1=30
The rod has a diameter of 40 mm. (Figure 1) It is subjected to the force system F₂ = 1410 N, Fy = 635 N, F₂ - 820 N. Figure F F 300 mm 100 N-m F. 100 mm B 1 of 1 Determine the normal stress that acts at point B. Express your answer to three significant figures and include appropriate units. ов - Submit Part B (TB)zy μA Submit Value Request Answer Determine the shear stress Try that acts at point B. Express your answer to three significant figures and include appropriate units. BLA Value Request Answer Units ļ 20011 Units COOL ? HEIT
use angle of 92 please
a=2.1m (1) c = 2m b = 3.1m d = 1.8m P = 30 kN WHAT IS THE AXIAL STRESS IN ROD 1 ? ANSWER IN MPa ROUNDED-OFF TO 2 DECIMAL PLACES B 2 dia of rod 1 = 13mm dia of rod 2 = 11 mm
(1) Given: b₁ B P=28 kN Square Bars b₁ = 57 mm (2) Q =9 kN b2 C b₂ = 19mm (3) Q R = 38kN ↑ D b3 = 38mm R WHAT IS THE AXAIL STRESS IN BAR 2? ANSWER IN MPa ROUNDED-OFF TO 2 DECIMAL PLACES. POSITIVE FOR TENSILE STRESS AND NEGATIVE FOR COMPRESSIVE STRESS.
Ineed answer within 20 minutes please please with my best wishes
The cantilevered rectangular bar is subjected to the force of 5 kip. Suppose that L = 17 in. (Figure 1) Figure 1.5 in. A 1.5 in. 1 in. 1 in. B L 1 of 1 > 1.5 in. 1.5 in.j T 3 in. H 3 in. 5 kip Part A Determine the principal stresses at point A Express your answers in kilopounds per square inch to three significant figures. Enter your answers separated by a comma. 01,02 = Submit Provide Feedback ΓΙ ΑΣΦ | | Request Answer vec 5 ? Review ksi Next >
Please solve all part
The bar is made from steel and has an allowable stress of allow = 19.7 ksi (Figure 1) Figure P 1.875 in. 0.75 in. -0.125 in. 1.25 in. r 0.25 in. 1 of 1 Part A Determine the maximum axial force P that can be applied to the bar. Express your answer to three significant figures and include the appropriate units. P = Submit μA Value Request Answer < Return to Assignment Units Provide Feedback ?
Example: Convert the change in length data in Table 3-2 to engineering stress and strain and plot a stress-strain curve Homework- help Table 3-2 The results of a tensile test of a 0.505 in. diameter aluminum alloy test bar, initial length (1o) = 2 in. Calculated LTO Load (Ib) Change in Length (in.) Stress (psi) Strain (in./in.) 0.000 1000 0.001 0.0005 4,993 14,978 24,963 34,948 37,445 39,442 39,941 39,691 37,944 3000 0.003 0.0015 5000 0.005 0.0025 7000 0.007 0.0035 7500 0.030 0.0150 7900 0.080 0.0400 8000 (maximum load) 0.120 0.0600 7950 0.160 0.0800 7600 (fracture) 0.205 0.1025
Solve correctly please.