(i) Newton's Second Law for m, in terms of weights of the blocks, m₁g, and m₂g, or their components in terms of the ramp angle 8, the tension in the string T and the normal reaction N₁ of the table on m₁ can be written as (use the coordinate axes for signs of different forces): =₁2₁,x ΣFx= =m₁a₁₁y ΣFy= (ii) Newton's Second Law for m₂ in terms of weights of the blocks, m₁g, and m₂g, or their components in terms of the ramp angle the tension in the string T and the normal reaction N₁ of the table on m, can be written as: Note: The motion of m₂ is along the y-direction only. = m₂a2,y ΣF= (iii) How are the magnitudes of a₁ and a₂ related? What are the directions of a₁ Magnitude: A. |a₁| is greater than la₂l B. |a₁| is less than |a₂| C. |a₁| is equal to |a₂| Direction: A. a, is in the positive x direction, and a2 is in the positive y-direction. B. a, is in the positive x direction, and a2 is in the negative y-direction. C. a, is in the negative x direction, and a2 is in the positive y-direction. D. a, is in the negative x direction, and a₂ is in the negative y-direction. Subpart 3: CALCULATE NUMERICAL VALUES Let m₁ = 1.9 kg block and m₂ = 3.4 kg block. The ramp angle 8 = 39⁰. (i) Find the acceleration for the two blocks. a = = 0 m (ii) Find the tension in the string. and a₂?

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(i) Newton’s Second Law for \( m_1 \) in terms of weights of the blocks, \( m_1 g \) and \( m_2 g \), or their components in terms of the ramp angle \( \theta \), the tension in the string \( T \), and the normal reaction \( N_1 \) of the table on \( m_1 \), can be written as (use the coordinate axes for signs of different forces):

\[
\sum F_{x} = \,\,\square\,\, = m_{1}a_{1,x}
\]

\[
\sum F_{y} = \,\,\square\,\, = m_{1}a_{1,y} = 0
\]

(ii) Newton’s Second Law for \( m_2 \) in terms of weights of the blocks, \( m_1 g \) and \( m_2 g \), or their components in terms of the ramp angle \( \theta \) the tension in the string \( T \) and the normal reaction \( N_1 \) of the table on \( m_1 \), can be written as:

*Note: The motion of \( m_2 \) is along the y-direction only.*

\[
\sum F_{y} = \,\,\square\,\, = m_{2}a_{2,y}
\]

(iii) How are the magnitudes of \( a_1 \) and \( a_2 \) related? What are the directions of \( a_1 \) and \( a_2 \)?

*Magnitude:*

A. \( |a_1| \) is greater than \( |a_2| \)  
B. \( |a_1| \) is less than \( |a_2| \)  
C. \( |a_1| \) is equal to \( |a_2| \)

*Direction:*

A. \( \vec{a_1} \) is in the positive x direction, and \( \vec{a_2} \) is in the positive y-direction.  
B. \( \vec{a_1} \) is in the positive x direction, and \( \vec{a_2} \) is in the negative y-direction.  
C. \( \vec{a_1} \) is in the negative x direction, and \( \vec{
Transcribed Image Text:(i) Newton’s Second Law for \( m_1 \) in terms of weights of the blocks, \( m_1 g \) and \( m_2 g \), or their components in terms of the ramp angle \( \theta \), the tension in the string \( T \), and the normal reaction \( N_1 \) of the table on \( m_1 \), can be written as (use the coordinate axes for signs of different forces): \[ \sum F_{x} = \,\,\square\,\, = m_{1}a_{1,x} \] \[ \sum F_{y} = \,\,\square\,\, = m_{1}a_{1,y} = 0 \] (ii) Newton’s Second Law for \( m_2 \) in terms of weights of the blocks, \( m_1 g \) and \( m_2 g \), or their components in terms of the ramp angle \( \theta \) the tension in the string \( T \) and the normal reaction \( N_1 \) of the table on \( m_1 \), can be written as: *Note: The motion of \( m_2 \) is along the y-direction only.* \[ \sum F_{y} = \,\,\square\,\, = m_{2}a_{2,y} \] (iii) How are the magnitudes of \( a_1 \) and \( a_2 \) related? What are the directions of \( a_1 \) and \( a_2 \)? *Magnitude:* A. \( |a_1| \) is greater than \( |a_2| \) B. \( |a_1| \) is less than \( |a_2| \) C. \( |a_1| \) is equal to \( |a_2| \) *Direction:* A. \( \vec{a_1} \) is in the positive x direction, and \( \vec{a_2} \) is in the positive y-direction. B. \( \vec{a_1} \) is in the positive x direction, and \( \vec{a_2} \) is in the negative y-direction. C. \( \vec{a_1} \) is in the negative x direction, and \( \vec{
**Problem Statement:**

1. A block of mass \( m_1 \) and a block of mass \( m_2 \) are connected by a light string as shown; the inclination of the ramp is \( \theta \). Friction is negligible.

   Assume that \( m_2 > m_1 \).

**Diagram Description:** 

The image depicts two blocks connected by a string over a pulley. Block \( m_1 \) is on an inclined plane with angle \( \theta \), and block \( m_2 \) hangs vertically off the side of the plane. The string runs over a pulley at the top of the incline. Block \( m_1 \) is labeled "1" and is placed on the ramp, while block \( m_2 \) is labeled "2" and hangs freely. The angle \( \theta \) is marked at the base of the incline.

**Subpart 1: Draw FBDs (Free Body Diagrams)**

In your notebook, draw free body diagrams of \( m_1 \) and \( m_2 \) using the template as shown below. The forces acting on the system are weights of the blocks, \( m_1g \) and \( m_2g \), the tension in the string \( T \), and the normal reaction \( N_1 \) of the table on \( m_1 \). 

**Note:** The choice of the coordinate axes for the two blocks can be different as shown below:

- For \( m_1 \):
  - Inclined x-y coordinate system with \( x \) parallel to the incline and \( y \) perpendicular.

- For \( m_2 \):
  - Standard x-y coordinate system with \( x \) horizontal and \( y \) vertical.

These considerations emphasize analyzing physics problems using different orientations of coordinate axes to simplify calculations based on the system setup.
Transcribed Image Text:**Problem Statement:** 1. A block of mass \( m_1 \) and a block of mass \( m_2 \) are connected by a light string as shown; the inclination of the ramp is \( \theta \). Friction is negligible. Assume that \( m_2 > m_1 \). **Diagram Description:** The image depicts two blocks connected by a string over a pulley. Block \( m_1 \) is on an inclined plane with angle \( \theta \), and block \( m_2 \) hangs vertically off the side of the plane. The string runs over a pulley at the top of the incline. Block \( m_1 \) is labeled "1" and is placed on the ramp, while block \( m_2 \) is labeled "2" and hangs freely. The angle \( \theta \) is marked at the base of the incline. **Subpart 1: Draw FBDs (Free Body Diagrams)** In your notebook, draw free body diagrams of \( m_1 \) and \( m_2 \) using the template as shown below. The forces acting on the system are weights of the blocks, \( m_1g \) and \( m_2g \), the tension in the string \( T \), and the normal reaction \( N_1 \) of the table on \( m_1 \). **Note:** The choice of the coordinate axes for the two blocks can be different as shown below: - For \( m_1 \): - Inclined x-y coordinate system with \( x \) parallel to the incline and \( y \) perpendicular. - For \( m_2 \): - Standard x-y coordinate system with \( x \) horizontal and \( y \) vertical. These considerations emphasize analyzing physics problems using different orientations of coordinate axes to simplify calculations based on the system setup.
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