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(i) Newton's Second Law for m, in terms of weights of the blocks, m₁g, and m₂g, or their components in terms of the ramp angle 8, the tension in the string T and the normal reaction N₁ of the table on m₁ can be written as (use the coordinate axes for signs of different forces): =₁2₁,x ΣFx= =m₁a₁₁y ΣFy= (ii) Newton's Second Law for m₂ in terms of weights of the blocks, m₁g, and m₂g, or their components in terms of the ramp angle the tension in the string T and the normal reaction N₁ of the table on m, can be written as: Note: The motion of m₂ is along the y-direction only. = m₂a2,y ΣF= (iii) How are the magnitudes of a₁ and a₂ related? What are the directions of a₁ Magnitude: A. |a₁| is greater than la₂l B. |a₁| is less than |a₂| C. |a₁| is equal to |a₂| Direction: A. a, is in the positive x direction, and a2 is in the positive y-direction. B. a, is in the positive x direction, and a2 is in the negative y-direction. C. a, is in the negative x direction, and a2 is in the positive y-direction. D. a, is in the negative x direction, and a₂ is in the negative y-direction. Subpart 3: CALCULATE NUMERICAL VALUES Let m₁ = 1.9 kg block and m₂ = 3.4 kg block. The ramp angle 8 = 39⁰. (i) Find the acceleration for the two blocks. a = = 0 m (ii) Find the tension in the string. and a₂?

(i) Newton's Second Law for m, in terms of weights of the blocks, m₁g, and m₂g, or their components in terms of the ramp angle 8, the tension in the string T and the normal reaction N₁ of the table on m₁ can be written as (use the coordinate axes for signs of different forces): =₁2₁,x ΣFx= =m₁a₁₁y ΣFy= (ii) Newton's Second Law for m₂ in terms of weights of the blocks, m₁g, and m₂g, or their components in terms of the ramp angle the tension in the string T and the normal reaction N₁ of the table on m, can be written as: Note: The motion of m₂ is along the y-direction only. = m₂a2,y ΣF= (iii) How are the magnitudes of a₁ and a₂ related? What are the directions of a₁ Magnitude: A. |a₁| is greater than la₂l B. |a₁| is less than |a₂| C. |a₁| is equal to |a₂| Direction: A. a, is in the positive x direction, and a2 is in the positive y-direction. B. a, is in the positive x direction, and a2 is in the negative y-direction. C. a, is in the negative x direction, and a2 is in the positive y-direction. D. a, is in the negative x direction, and a₂ is in the negative y-direction. Subpart 3: CALCULATE NUMERICAL VALUES Let m₁ = 1.9 kg block and m₂ = 3.4 kg block. The ramp angle 8 = 39⁰. (i) Find the acceleration for the two blocks. a = = 0 m (ii) Find the tension in the string. and a₂?

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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(i) Newton's Second Law for m, in terms of weights of the blocks, m₁g, and m₂g, or their components in terms of the ramp angle 8, the tension in the string 7 and the normal reaction N₁ of the table on m₁ can be written as (use the coordinate axes for signs of different forces): =m₁a₁₁x =m₁a₁₁y =0 (ii) Newton's Second Law for m₂ in terms of weights of the blocks, m₁g, and m₂g, or their components in terms of the ramp angle the tension in the string 7 and the normal reaction N₁ of the table on m, can be written as: Note: The motion of m₂ is along the y-direction only. ΣF= ΣFx= ΣF= = m₂a2,y (iii) How are the magnitudes of a₁ and a₂ related? What are the directions of a, and a₂? Magnitude: A. |a₁| is greater than la₂l B. |a₁| is less than |a₂| C. |a₁| is equal to |a₂| Direction: A. a, is in the positive x direction, and a₂ is in the positive y-direction. B. a₁ is in the positive x direction, and a₂ is in the negative y-direction. C. 2₁ is in the positive y-direction. D. a, is in the negative x direction, and a₂ is in the negative y-direction. is in the negative x direction, and a2 Subpart 3: CALCULATE NUMERICAL VALUES Let m₁ (i) Find the acceleration for the two blocks. = 1.9 kg block and m₂ = 3.4 kg block. The ramp angle 0 = 39⁰. m s² (ii) Find the tension in the string. a =
Transcribed Image Text:(i) Newton's Second Law for m, in terms of weights of the blocks, m₁g, and m₂g, or their components in terms of the ramp angle 8, the tension in the string 7 and the normal reaction N₁ of the table on m₁ can be written as (use the coordinate axes for signs of different forces): =m₁a₁₁x =m₁a₁₁y =0 (ii) Newton's Second Law for m₂ in terms of weights of the blocks, m₁g, and m₂g, or their components in terms of the ramp angle the tension in the string 7 and the normal reaction N₁ of the table on m, can be written as: Note: The motion of m₂ is along the y-direction only. ΣF= ΣFx= ΣF= = m₂a2,y (iii) How are the magnitudes of a₁ and a₂ related? What are the directions of a, and a₂? Magnitude: A. |a₁| is greater than la₂l B. |a₁| is less than |a₂| C. |a₁| is equal to |a₂| Direction: A. a, is in the positive x direction, and a₂ is in the positive y-direction. B. a₁ is in the positive x direction, and a₂ is in the negative y-direction. C. 2₁ is in the positive y-direction. D. a, is in the negative x direction, and a₂ is in the negative y-direction. is in the negative x direction, and a2 Subpart 3: CALCULATE NUMERICAL VALUES Let m₁ (i) Find the acceleration for the two blocks. = 1.9 kg block and m₂ = 3.4 kg block. The ramp angle 0 = 39⁰. m s² (ii) Find the tension in the string. a =
1. A block of mass m, and a block of mass m₂ are connected by a light string as shown; the inclination of the ramp is 8. Friction is negligible. Assume that m₂ > m₁. Ꮎ 1 0 Subpart 1: Draw FBDs In your notebook, draw a free body diagrams of m, and m₂ using the template as shown below. The forces acting on the system are weights of the blocks, m₁g, and m₂g, the tension in the string T and the normal reaction N₁ of the table on m₁. Note: The choice of the coordinate axes for the two blocks can be different as shown below: m₂ 2 y
Transcribed Image Text:1. A block of mass m, and a block of mass m₂ are connected by a light string as shown; the inclination of the ramp is 8. Friction is negligible. Assume that m₂ > m₁. Ꮎ 1 0 Subpart 1: Draw FBDs In your notebook, draw a free body diagrams of m, and m₂ using the template as shown below. The forces acting on the system are weights of the blocks, m₁g, and m₂g, the tension in the string T and the normal reaction N₁ of the table on m₁. Note: The choice of the coordinate axes for the two blocks can be different as shown below: m₂ 2 y
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