### Problem Statement**Concept: Static Friction and Kinematics**(c) The floor of a railroad flatcar is loaded with loose crates having a coefficient of static friction of 0.25 with the floor. If the train is initially moving at a speed of 48 km/h, in how short a distance can the train be stopped at constant acceleration without causing the crates to slide over the floor?**Explanation:**This problem involves understanding the principles of static friction and kinematics. Here are the key steps to solve such a problem:1. **Coefficient of Static Friction:** This is a measure of how much force is needed to start moving an object at rest. Given as 0.25 in this scenario.2. **Initial Speed:** The initial speed of the train is given as 48 km/h. For calculation purposes, this speed should be converted into meters per second (m/s).3. **Determining Stopping Distance:** Using the coefficient of static friction, calculate the maximum deceleration the crates can withstand without sliding. Then, apply kinematic equations to find the shortest stopping distance.### Solution Outline:1. **Convert Speed:** - Convert 48 km/h to m/s. - \( 48 \text{ km/h} = \frac{48 \times 1000}{3600} \text{ m/s} = 13.33 \text{ m/s} \)2. **Maximum Acceleration:** - Using the relationship \( f = \mu \times N \) where \( f \) is the force of friction, \( \mu \) is the coefficient of static friction, and \( N \) is the normal force. With the gravitational acceleration \( g = 9.8 \text{ m/s}^2 \): - \( \text{Maximum Acceleration} = \mu \times g = 0.25 \times 9.8 = 2.45 \text{ m/s}^2 \)3. **Kinematic Equation:** - Use \( v^2 = u^2 + 2as \) where \( v \) is the final velocity (0 m/s, since the train stops), \( u \) is the initial velocity, \( a \) is the acceleration, and \( s \) is the stopping distance. - Rearrange to find \( s \): \( s = \frac{u^2}{

Solution:- given μs = 0.25u = 48 km/hr=48×518 = 13.33 m/s

c) The floor of a railroad flatcar is loaded with loose crates having a coefficient of static friction of 0.25 with the floor. If the train is initially moving at a speed of 48 km/h, in how short a distance can the train be stopped at constant acceleration without causing the crates to slide over the floor?

c) The floor of a railroad flatcar is loaded with loose crates having a coefficient of static friction of 0.25 with the floor. If the train is initially moving at a speed of 48 km/h, in how short a distance can the train be stopped at constant acceleration without causing the crates to slide over the floor?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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