### Problem Statement**Concept: Static Friction and Kinematics**(c) The floor of a railroad flatcar is loaded with loose crates having a coefficient of static friction of 0.25 with the floor. If the train is initially moving at a speed of 48 km/h, in how short a distance can the train be stopped at constant acceleration without causing the crates to slide over the floor?**Explanation:**This problem involves understanding the principles of static friction and kinematics. Here are the key steps to solve such a problem:1. **Coefficient of Static Friction:** This is a measure of how much force is needed to start moving an object at rest. Given as 0.25 in this scenario.2. **Initial Speed:** The initial speed of the train is given as 48 km/h. For calculation purposes, this speed should be converted into meters per second (m/s).3. **Determining Stopping Distance:** Using the coefficient of static friction, calculate the maximum deceleration the crates can withstand without sliding. Then, apply kinematic equations to find the shortest stopping distance.### Solution Outline:1. **Convert Speed:** - Convert 48 km/h to m/s. - \( 48 \text{ km/h} = \frac{48 \times 1000}{3600} \text{ m/s} = 13.33 \text{ m/s} \)2. **Maximum Acceleration:** - Using the relationship \( f = \mu \times N \) where \( f \) is the force of friction, \( \mu \) is the coefficient of static friction, and \( N \) is the normal force. With the gravitational acceleration \( g = 9.8 \text{ m/s}^2 \): - \( \text{Maximum Acceleration} = \mu \times g = 0.25 \times 9.8 = 2.45 \text{ m/s}^2 \)3. **Kinematic Equation:** - Use \( v^2 = u^2 + 2as \) where \( v \) is the final velocity (0 m/s, since the train stops), \( u \) is the initial velocity, \( a \) is the acceleration, and \( s \) is the stopping distance. - Rearrange to find \( s \): \( s = \frac{u^2}{

Solution:- given μs = 0.25u = 48 km/hr=48×518 = 13.33 m/s

c) The floor of a railroad flatcar is loaded with loose crates having a coefficient of static friction of 0.25 with the floor. If the train is initially moving at a speed of 48 km/h, in how short a distance can the train be stopped at constant acceleration without causing the crates to slide over the floor?

c) The floor of a railroad flatcar is loaded with loose crates having a coefficient of static friction of 0.25 with the floor. If the train is initially moving at a speed of 48 km/h, in how short a distance can the train be stopped at constant acceleration without causing the crates to slide over the floor?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: A car is traveling at 41.0 km/h on a flat highway. (a) If the coefficient of friction between road…

Q: In a mail-sorting facility, a 2.50-kg package slides down an inclined plane that makes an angle of…

Q: Fig. 2 F1 +y 55.0 - +x 54.0 N F2 2. Fig. 2 shows a 25.0-kg crate that is initially at rest. Note…

A: Given: Mass of crate: 25 kg kinetic friction: μk=0.350 Force F1 has two components in x and y…

Q: Terminal velocity is the maximum velocity attainable by an object as it falls through air. Since the…

Q: Option #2: A roller coaster car is at the top of a huge hill and is at rest briefly. Then it rolls…

Q: Alter a tornado, you decide to go check on your mother' house. You start driving down an 11 degree…

Q: Under what condition(s) will an object be in equilibrium? If the object is either moving with…

A: A object is claimed to be in equal state if the net force acting on the object is nought(0). By…

Q: You are trying to push a box with a fragile vase sitting on top of it across the room. Starting the…

A: Given: The box starts from rest. Distance moved (s) by the vase and the box is 5 meters. Time (t)…

Q: A car is traveling at 48.0 km/h on a flat highway. If the coefficient of friction between road and…

Q: A car is traveling at 40.0 km/h on a flat highway. (a) If the coefficient of friction between road…

Q: On an alien planet, an object moving at 4.0 m/s on the horizontal ground comes to rest after…

Q: Problem 6: In the two cases shown below, a person is standing on a scale in an elevator. The…

A: It is mentioned that the weight of both persons is the same and they are moving at a constant speed.

Q: A car is traveling at 46.0 mi/h on a horizontal highway. (a) If the coefficient of static friction…

A: Given Data: Initial speed of the car (u) = 47 mi/h = 21.0 m/s. Final speed of the car (v) = 0 m/s.…

Q: A man is pulling two boxes, one on top of the other, up the ramp shown by pulling on a rope parallel…

A: We need to find out the magnitude of the maximum acceleration the man can pull the boxes up the ramp…

Q: A M1 =1000-kg car is on a rough ramp that is inclined at θ = 20° above the horizontal. It is…

Q: A pickup truck is carrying a 10.0 kgkg toolbox, but the tailgate of the truck is missing, so the box…

A: Given Mass of the tool box m = 10.0 kg Coefficient of kinetic friction μs = 0.34 Coefficient of…

Q: Part F A microwave oven of mass 10.0 kg is pushed a distance 8.45 m up the sloping surface of a…

A: The oven of mass 10 kg is being pushed up an incline angled at 38.6 with the horizontal. The oven is…

Q: A heavy box of mass M is found at rest on an inclined loading ramp as indicated in the figure. The…

Q: The driver of a car applies the brakes, and the car starts to skid. If the coefficient of friction…

Q: a mass is given an initial velocity v0= 3.4ms up a 15 degree incline. a) if the coefficient of…

A: Given data: Initial velocity of the mass, vo=3.4 m/s Inclined angle, θ=15o Coefficient of kinetics…

Q: A pickup truck carries cans of paint in the back bed. The coefficient of static friction between the…

Q: The floor of a railroad flatcar is loaded with loose crates having a coefficient of static friction…

A: Initial velocity (U)= 51 km/h = 14.16 m/s Final velocity (V) = 0 m/s Coefficient of friction (µ) =…

Q: VA = 30 m/s A Vg = 20 m/s B

Q: A car is traveling at 51.0 km/h on a flat highway. (a) If the coefficient of friction between road…

Q: Two blocks of masses M1 = 3.5 kg and M2 = 5.7 kg are at rest on a horizontal surface with a…

Q: Two packing crates of masses m, = 10.0 kg and m, = 7.30 kg are connected by a light string that…

Q: A 620 kg packing crate is being pulled up a 16 degrees-inclined plane by a rope. The rope is…

A: Given : Mass of crate: 620 kg Inclination of plane θ = 160 Coefficient of kinetic friction : μ=0.3…

Q: A moving truck (m = 3200 kg) is parked on a hill that is inclined at an angle of 11◦ from the…

Q: You are given the job of moving a refrigerator with a mass of 1.8 x 102 kg across a horizontal…

A: Given: The mass of the object is 1.8x102 kg. The coefficient of the kinetic friction is 0.45.

Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

### Problem Statement

**Concept: Static Friction and Kinematics**

(c) The floor of a railroad flatcar is loaded with loose crates having a coefficient of static friction of 0.25 with the floor. If the train is initially moving at a speed of 48 km/h, in how short a distance can the train be stopped at constant acceleration without causing the crates to slide over the floor?

**Explanation:**

This problem involves understanding the principles of static friction and kinematics. Here are the key steps to solve such a problem:

1. **Coefficient of Static Friction:** This is a measure of how much force is needed to start moving an object at rest. Given as 0.25 in this scenario.

2. **Initial Speed:** The initial speed of the train is given as 48 km/h. For calculation purposes, this speed should be converted into meters per second (m/s).

3. **Determining Stopping Distance:** Using the coefficient of static friction, calculate the maximum deceleration the crates can withstand without sliding. Then, apply kinematic equations to find the shortest stopping distance.

### Solution Outline:

1. **Convert Speed:**
- Convert 48 km/h to m/s.
- \( 48 \text{ km/h} = \frac{48 \times 1000}{3600} \text{ m/s} = 13.33 \text{ m/s} \)

2. **Maximum Acceleration:**
- Using the relationship \( f = \mu \times N \) where \( f \) is the force of friction, \( \mu \) is the coefficient of static friction, and \( N \) is the normal force. With the gravitational acceleration \( g = 9.8 \text{ m/s}^2 \):
- \( \text{Maximum Acceleration} = \mu \times g = 0.25 \times 9.8 = 2.45 \text{ m/s}^2 \)

3. **Kinematic Equation:**
- Use \( v^2 = u^2 + 2as \) where \( v \) is the final velocity (0 m/s, since the train stops), \( u \) is the initial velocity, \( a \) is the acceleration, and \( s \) is the stopping distance.
- Rearrange to find \( s \): \( s = \frac{u^2}{

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

To meet a U.S. Postal Service requirement, employees’ footwear must have a coefficient of static friction of 0.500 or more on a specified tile surface. A typical athletic shoe has a coefficient of 0. 800. In an emergency, what is the minimum time interval in which a person starting from rest can move 3.00 m on the tile surface if she is wearing (a) footwear meeting the Postal Service minimum and (b) a typical athletic shoe?
A cougar bites a llama of mass m and drags it across some rough horizontal ground. The cougar applies a horizontal force of magnitude F, and the llama is dragged at a constant velocity. The coefficient of kinetic friction is μk. While the cougar applies the force F, the magnitude of the kinetic friction force, fk , on the llama obeys: a)F > µk m g > fk b)F = fk = µk m gc)F = fk < µk m gd)cannot answer, not enough information givene) F > fk = µk m g
In a movie, a stuntman places himself on the vertical front of a truck as the truck accelerates. The coefficient of static friction between the stuntman and the truck is 0.370. The stuntman is not standing on anything but can “stick” to the front of the truck as long as the truck continues to accelerate. What minimum forward acceleration will keep the stuntman on the front of the truck?
A man is driving his car with speed 49.0 mi/h on a horizontal stretch of road. (a) When the road is wet, the coefficient of static friction between the road and the tires is 0.102. Find the minimum stopping distance (in m). m == (b) When the road is dry, H, = 0.598. Find the minimum stopping distance (in m). m
Police examine the scene of an accident involving two cars, which is parked. The skid marks of the moving car, which nearly came to a stop before the collision, is 80 meters long. The coefficient of kinetic friction between rubber and the pavement is about 0.80. Estimate the initial speed of the car.
A student, crazed by final exams, uses a force of magnitude 80 N and angle u =70 to push a 5.0 kg block across the ceiling of his room ). If the coefficient of kinetic friction between the block and the ceiling is 0.40, what is the magnitude of the block’s acceleration?
A large cube (mass = M) being accelerated across a horizontal frictionless surface by a horizontal force . A small cube (mass = m) is in contact with the front surface of the large cube and will slide downward unless is sufficiently large. The coefficient of static friction between the cubes is u. What is the smallest magnitude that F can have in order to keep the small cube from sliding downward?