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I need help with the last row of the table ptotal = m1v1 + m2v2 and ptotal = (m1 + m2) V12

I need help with the last row of the table ptotal = m1v1 + m2v2 and ptotal = (m1 + m2) V12

An Introduction to Physical Science
An Introduction to Physical Science
14th Edition
ISBN:9781305079137
Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Publisher:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Chapter3: Force And Motion
Section3.7: Momentum
Problem 3.4CE: Suppose you were not given the values of the masses but only that m1 = m and m2 = 3m. What could you...
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I need help with the last row of the table ptotal = m1v1 + m2v2 and ptotal = (m1 + m2) V12
The table provides various data related to the motion of two masses and their velocities. Below is an explanation of the contents of the table. ### Table Columns: - **\( m_1 \)**: Mass 1 (in kg) - **\( m_2 \)**: Mass 2 (in kg) - **\( \bar{v}_1 \)**: Initial velocity of Mass 1 (in m/s) - **\( \bar{v}_2 \)**: Initial velocity of Mass 2 (in m/s) - **\( \bar{p}_{\text{total}} \)**: Total momentum (in kg·m/s) - **\( \bar{v}'_{12} \)**: Final velocity of the combined mass system (in m/s) ### Table Data: | \( m_1 \) | \( m_2 \) | \( \bar{v}_1 \) | \( \bar{v}_2 \) | \( \bar{p}_{\text{total}} \) | \( \bar{v}'_{12} \) | |-----------|-----------|-----------------|-----------------|-----------------|-----------------| | 1.20 kg | 1.20 kg | +1.50 m/s | -1.80 m/s | -0.36 kg·m/s | 1.50 m/s | | 2.40 kg | 4.80 kg | +1.30 m/s | 0.80 m/s | 7.00 kg·m/s | 0.97 m/s | | 1.50 kg | 5.50 kg | +3.20 m/s | +0.800 m/s | 9.20 kg·m/s | 1.31 m/s | | 2.50 kg | * | 1.20 m/s | * | * | 0.0 m/s | ### Notes: - An asterisk (*) indicates missing data points. - The "*" denotes that zero mass or speed is not an option. To solve the problem, find the actual values for these cases. - The highlighted values suggest key figures or outcomes, likely for solving or analyzing the scenario further. This table is useful for understanding the principles of momentum and the effects of velocity changes on different masses in motion.
Transcribed Image Text:The table provides various data related to the motion of two masses and their velocities. Below is an explanation of the contents of the table. ### Table Columns: - **\( m_1 \)**: Mass 1 (in kg) - **\( m_2 \)**: Mass 2 (in kg) - **\( \bar{v}_1 \)**: Initial velocity of Mass 1 (in m/s) - **\( \bar{v}_2 \)**: Initial velocity of Mass 2 (in m/s) - **\( \bar{p}_{\text{total}} \)**: Total momentum (in kg·m/s) - **\( \bar{v}'_{12} \)**: Final velocity of the combined mass system (in m/s) ### Table Data: | \( m_1 \) | \( m_2 \) | \( \bar{v}_1 \) | \( \bar{v}_2 \) | \( \bar{p}_{\text{total}} \) | \( \bar{v}'_{12} \) | |-----------|-----------|-----------------|-----------------|-----------------|-----------------| | 1.20 kg | 1.20 kg | +1.50 m/s | -1.80 m/s | -0.36 kg·m/s | 1.50 m/s | | 2.40 kg | 4.80 kg | +1.30 m/s | 0.80 m/s | 7.00 kg·m/s | 0.97 m/s | | 1.50 kg | 5.50 kg | +3.20 m/s | +0.800 m/s | 9.20 kg·m/s | 1.31 m/s | | 2.50 kg | * | 1.20 m/s | * | * | 0.0 m/s | ### Notes: - An asterisk (*) indicates missing data points. - The "*" denotes that zero mass or speed is not an option. To solve the problem, find the actual values for these cases. - The highlighted values suggest key figures or outcomes, likely for solving or analyzing the scenario further. This table is useful for understanding the principles of momentum and the effects of velocity changes on different masses in motion.
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