I need help with f, g and h ---**Study on the Relationship Between Phone Usage and Weight****Research Question:** What is the relationship between the number of minutes per day a woman spends talking on the phone and the woman's weight? The time on the phone and weight for 8 women are shown in the table below.| Time (minutes) | 81 | 52 | 52 | 64 | 62 | 23 | 36 | 30 ||----------------|----|----|----|----|----|----|----|----|| Pounds | 119| 119| 116| 117| 128| 105| 116| 105|### a. Correlation Coefficient- Find the correlation coefficient: \( r = \) ⬜ (Round to 2 decimal places.)### b. Hypothesis for Correlation- The null and alternative hypotheses for correlation are: - \( H_0 \): ⬜ \( = 0 \) - \( H_1 \): ⬜ \( \neq 0 \) - The p-value is: \(\_\_\_\_\_\_\_\_\_\_\_\) (Round to four decimal places.)### c. Hypothesis Test Conclusion- Use a level of significance of \(\alpha = 0.05\) to state the conclusion of the hypothesis test in the context of the study. - There is statistically significant evidence to conclude that there is a correlation between the time women spend on the phone and their weight. Thus, the regression line is useful. - There is statistically significant evidence to conclude that a woman who spends more time on the phone will weigh more than a woman who spends less time on the phone. - There is statistically insignificant evidence to conclude that there is a correlation between the time women spend on the phone and their weight. Thus, the use of the regression line is not appropriate. - There is statistically insignificant evidence to conclude that a woman who spends more time on the phone will weigh more than a woman who spends less time on the phone.### d. Coefficient of Determination- \( r^2 = \) ⬜ (Round to two decimal places.)### e. Interpretation of \( r^2 \)- There is a 56% chance that the regression line will be a good predictor for women's weight based on their time spent on the phone.- 56% of all women will have ### Linear Regression Analysis#### Reducing Variation in Predictions- There is a large variation in women's weight, but if you only look at women with a fixed weight, this variation on average is reduced by 56%.- Given any group of women who all weigh the same amount, 56% of all these women will weigh the predicted amount.#### Linear Regression Equation**f. The equation of the linear regression line is:**\[ \hat{y} = \_\_\_\_ + \_\_\_\_x \]*(Please show your answers to two decimal places)*#### Predicting Weight Based on Time Spent on the Phone**g. Use the model to predict the weight of a woman who spends 40 minutes on the phone.**\[ \text{Weight} = \_\_\_\_ \]*(Please round your answer to the nearest whole number.)*#### Interpreting the Slope in Context**h. Interpret the slope of the regression line in the context of the question:**- \[ \circ \] As x goes up, y goes up.- \[ \circ \] For every additional minute women spend on the phone, they tend to weigh on average 0.29 additional pounds.- \[ \circ \] The slope has no practical meaning since you cannot predict a woman's weight.#### Interpreting the Y-Intercept in Context**i. Interpret the y-intercept in the context of the question:**- \[ \circ \] The average woman's weight is predicted to be 101.- \[ \circ \] If a woman does not spend any time talking on the phone, then that woman will weigh 101 pounds.- \[ \circ \] The y-intercept has no practical meaning for this study.- \[ \circ \] The best prediction for the weight of a woman who does not spend any time talking on the phone is 101 pounds.### Additional Resources- [Helpful Video on the Linear Regression Line](#)- [Helpful Video on Correlation](#)- [Helpful Video on Hypothesis Tests for Correlation](#)### Hints[+] Click on the links above for detailed instructional videos and further reading materials on each topic.

The given data is, Time(X) Weight(Y) 81 119 52 119 52 116 64 117 62 128 23 105 36…

Answered: I need help with f, g and h

I need help with f, g and h

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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