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I need help with f, g and h
---

**Study on the Relationship Between Phone Usage and Weight**

**Research Question:** What is the relationship between the number of minutes per day a woman spends talking on the phone and the woman's weight? The time on the phone and weight for 8 women are shown in the table below.

| Time (minutes) | 81 | 52 | 52 | 64 | 62 | 23 | 36 | 30 |
|----------------|----|----|----|----|----|----|----|----|
| Pounds         | 119| 119| 116| 117| 128| 105| 116| 105|

### a. Correlation Coefficient
- Find the correlation coefficient: \( r = \) ⬜ (Round to 2 decimal places.)

### b. Hypothesis for Correlation
- The null and alternative hypotheses for correlation are:
  - \( H_0 \): ⬜ \( = 0 \)
  - \( H_1 \): ⬜ \( \neq 0 \)
  - The p-value is: \(\_\_\_\_\_\_\_\_\_\_\_\) (Round to four decimal places.)

### c. Hypothesis Test Conclusion
- Use a level of significance of \(\alpha = 0.05\) to state the conclusion of the hypothesis test in the context of the study.
  - There is statistically significant evidence to conclude that there is a correlation between the time women spend on the phone and their weight. Thus, the regression line is useful.
  - There is statistically significant evidence to conclude that a woman who spends more time on the phone will weigh more than a woman who spends less time on the phone.
  - There is statistically insignificant evidence to conclude that there is a correlation between the time women spend on the phone and their weight. Thus, the use of the regression line is not appropriate.
  - There is statistically insignificant evidence to conclude that a woman who spends more time on the phone will weigh more than a woman who spends less time on the phone.

### d. Coefficient of Determination
- \( r^2 = \) ⬜ (Round to two decimal places.)

### e. Interpretation of \( r^2 \)
- There is a 56% chance that the regression line will be a good predictor for women's weight based on their time spent on the phone.
- 56% of all women will have
Transcribed Image Text:--- **Study on the Relationship Between Phone Usage and Weight** **Research Question:** What is the relationship between the number of minutes per day a woman spends talking on the phone and the woman's weight? The time on the phone and weight for 8 women are shown in the table below. | Time (minutes) | 81 | 52 | 52 | 64 | 62 | 23 | 36 | 30 | |----------------|----|----|----|----|----|----|----|----| | Pounds | 119| 119| 116| 117| 128| 105| 116| 105| ### a. Correlation Coefficient - Find the correlation coefficient: \( r = \) ⬜ (Round to 2 decimal places.) ### b. Hypothesis for Correlation - The null and alternative hypotheses for correlation are: - \( H_0 \): ⬜ \( = 0 \) - \( H_1 \): ⬜ \( \neq 0 \) - The p-value is: \(\_\_\_\_\_\_\_\_\_\_\_\) (Round to four decimal places.) ### c. Hypothesis Test Conclusion - Use a level of significance of \(\alpha = 0.05\) to state the conclusion of the hypothesis test in the context of the study. - There is statistically significant evidence to conclude that there is a correlation between the time women spend on the phone and their weight. Thus, the regression line is useful. - There is statistically significant evidence to conclude that a woman who spends more time on the phone will weigh more than a woman who spends less time on the phone. - There is statistically insignificant evidence to conclude that there is a correlation between the time women spend on the phone and their weight. Thus, the use of the regression line is not appropriate. - There is statistically insignificant evidence to conclude that a woman who spends more time on the phone will weigh more than a woman who spends less time on the phone. ### d. Coefficient of Determination - \( r^2 = \) ⬜ (Round to two decimal places.) ### e. Interpretation of \( r^2 \) - There is a 56% chance that the regression line will be a good predictor for women's weight based on their time spent on the phone. - 56% of all women will have
### Linear Regression Analysis

#### Reducing Variation in Predictions
- There is a large variation in women's weight, but if you only look at women with a fixed weight, this variation on average is reduced by 56%.
- Given any group of women who all weigh the same amount, 56% of all these women will weigh the predicted amount.

#### Linear Regression Equation
**f. The equation of the linear regression line is:**

\[ \hat{y} = \_\_\_\_ + \_\_\_\_x \]
*(Please show your answers to two decimal places)*

#### Predicting Weight Based on Time Spent on the Phone
**g. Use the model to predict the weight of a woman who spends 40 minutes on the phone.**
\[ \text{Weight} = \_\_\_\_ \]
*(Please round your answer to the nearest whole number.)*

#### Interpreting the Slope in Context
**h. Interpret the slope of the regression line in the context of the question:**
- \[ \circ \] As x goes up, y goes up.
- \[ \circ \] For every additional minute women spend on the phone, they tend to weigh on average 0.29 additional pounds.
- \[ \circ \] The slope has no practical meaning since you cannot predict a woman's weight.

#### Interpreting the Y-Intercept in Context
**i. Interpret the y-intercept in the context of the question:**
- \[ \circ \] The average woman's weight is predicted to be 101.
- \[ \circ \] If a woman does not spend any time talking on the phone, then that woman will weigh 101 pounds.
- \[ \circ \] The y-intercept has no practical meaning for this study.
- \[ \circ \] The best prediction for the weight of a woman who does not spend any time talking on the phone is 101 pounds.

### Additional Resources
- [Helpful Video on the Linear Regression Line](#)
- [Helpful Video on Correlation](#)
- [Helpful Video on Hypothesis Tests for Correlation](#)

### Hints
[+] Click on the links above for detailed instructional videos and further reading materials on each topic.
Transcribed Image Text:### Linear Regression Analysis #### Reducing Variation in Predictions - There is a large variation in women's weight, but if you only look at women with a fixed weight, this variation on average is reduced by 56%. - Given any group of women who all weigh the same amount, 56% of all these women will weigh the predicted amount. #### Linear Regression Equation **f. The equation of the linear regression line is:** \[ \hat{y} = \_\_\_\_ + \_\_\_\_x \] *(Please show your answers to two decimal places)* #### Predicting Weight Based on Time Spent on the Phone **g. Use the model to predict the weight of a woman who spends 40 minutes on the phone.** \[ \text{Weight} = \_\_\_\_ \] *(Please round your answer to the nearest whole number.)* #### Interpreting the Slope in Context **h. Interpret the slope of the regression line in the context of the question:** - \[ \circ \] As x goes up, y goes up. - \[ \circ \] For every additional minute women spend on the phone, they tend to weigh on average 0.29 additional pounds. - \[ \circ \] The slope has no practical meaning since you cannot predict a woman's weight. #### Interpreting the Y-Intercept in Context **i. Interpret the y-intercept in the context of the question:** - \[ \circ \] The average woman's weight is predicted to be 101. - \[ \circ \] If a woman does not spend any time talking on the phone, then that woman will weigh 101 pounds. - \[ \circ \] The y-intercept has no practical meaning for this study. - \[ \circ \] The best prediction for the weight of a woman who does not spend any time talking on the phone is 101 pounds. ### Additional Resources - [Helpful Video on the Linear Regression Line](#) - [Helpful Video on Correlation](#) - [Helpful Video on Hypothesis Tests for Correlation](#) ### Hints [+] Click on the links above for detailed instructional videos and further reading materials on each topic.
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