I need help calculating the last value using my zone average molarity of KMnO4K, 0.01366 M, and my calculated value for the average molarity of KMnO4, 0.0114809 M
I need help calculating the last value using my zone average molarity of KMnO4K, 0.01366 M, and my calculated value for the average molarity of KMnO4, 0.0114809 M
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I need help calculating the last value using my zone average molarity of KMnO4K, 0.01366 M, and my calculated value for the average molarity of KMnO4, 0.0114809 M.
![Part 2. Determination of the Mass Percent of FeS0, • 7H,0
4.
Experimental Data
Sample #_
Pill #1
Pill #2
1.0412g
1,0393g
Mass of boat and ground pill
0.6825g
0.6632g
Mass of boat
Initial burette reading
27.0mL
28.9 mL
Final burette reading
44,2mL
43.5mk
Reaction
MnO, + 5 Fe?+ + 8 H* → 5 Fe + Mn² + 4 H,0
Calculated Values
Use your [KMNO,Jv = 0.0114809
from Part 1
%3D
Mass of ground pill
0.3587
0.3711
Volume of KMnO,
17,2
14.6
Moles of KMNO,
0.00019747
0.000167621
Moles of Fe2+
0.000987355
0.000838105
Moles of FeSO, • 7H,O
0,000987355
0.000838105
Mass of FeSO, • 7H,O
0.274500
0.233000
Mass % FeSO, • 7H,0
76,5260
62.78631
69.6561
Average mass % FeSO, • 7H,O
Additional calculation (see page 4-7 and Worksheet)
Average mass % FeSO, • 7H,O using zone [KMnO̟]
4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa8a9fa33-1e6b-41ec-86b7-17f0915493bf%2F2b1129b7-0a47-4729-8378-c6da3ae71ba1%2Fjxnbf4p8_processed.png&w=3840&q=75)
Transcribed Image Text:Part 2. Determination of the Mass Percent of FeS0, • 7H,0
4.
Experimental Data
Sample #_
Pill #1
Pill #2
1.0412g
1,0393g
Mass of boat and ground pill
0.6825g
0.6632g
Mass of boat
Initial burette reading
27.0mL
28.9 mL
Final burette reading
44,2mL
43.5mk
Reaction
MnO, + 5 Fe?+ + 8 H* → 5 Fe + Mn² + 4 H,0
Calculated Values
Use your [KMNO,Jv = 0.0114809
from Part 1
%3D
Mass of ground pill
0.3587
0.3711
Volume of KMnO,
17,2
14.6
Moles of KMNO,
0.00019747
0.000167621
Moles of Fe2+
0.000987355
0.000838105
Moles of FeSO, • 7H,O
0,000987355
0.000838105
Mass of FeSO, • 7H,O
0.274500
0.233000
Mass % FeSO, • 7H,0
76,5260
62.78631
69.6561
Average mass % FeSO, • 7H,O
Additional calculation (see page 4-7 and Worksheet)
Average mass % FeSO, • 7H,O using zone [KMnO̟]
4
![Additional Calculation:
instead of your [KMNO,]. The
The results for Part 2 could be recalculated using the [KMN0,]cne average
formula below will give the average mass percent of FeSO, • 7H,O using the zone average [KMNO¸],
without repeating all the calculations. Show your work.
[KMNO (zone)
%3D
(zone KMNO4)
[KMNO (yours)
Avg mass % FeSO, • 7H,O4one KMnO,) = Avg mass % FeSO, • 7H,Oyour KMnO,)
(your KMNO4)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa8a9fa33-1e6b-41ec-86b7-17f0915493bf%2F2b1129b7-0a47-4729-8378-c6da3ae71ba1%2Fntf3k2e_processed.png&w=3840&q=75)
Transcribed Image Text:Additional Calculation:
instead of your [KMNO,]. The
The results for Part 2 could be recalculated using the [KMN0,]cne average
formula below will give the average mass percent of FeSO, • 7H,O using the zone average [KMNO¸],
without repeating all the calculations. Show your work.
[KMNO (zone)
%3D
(zone KMNO4)
[KMNO (yours)
Avg mass % FeSO, • 7H,O4one KMnO,) = Avg mass % FeSO, • 7H,Oyour KMnO,)
(your KMNO4)
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