For this question it’s telling me use KCI which stands for potassium chloride so do I use KCl, (1 atom X 39.0983 Potassium) + (1 atom X 35.453 Chlorine) = (74.5513 g/mol) and use that with 10 ML of 20% Solution. I’ve been stuck on figuring out what I could do for this question. I want a long clarification and steps on it so it could help me know if I’m correct as I’m doing this question on my notebook. **Calculating the Mass of KCl in a Solution****Question:**How many grams of KCl are there in 10 mL of 20% solution?**Explanation:**To determine the mass of potassium chloride (KCl) in a solution, we need to understand the concept of percentage concentration. A 20% KCl solution means that there are 20 grams of KCl in every 100 mL of solution.**Step-by-Step Calculation:**1. Given: - Percentage concentration (C) = 20% - Volume of solution (V) = 10 mL2. Understand the percentage: - 20% solution means 20 grams of KCl in 100 mL of solution.3. Use the percentage concentration to setup a proportion: - If 100 mL solution contains 20 grams of KCl, - Then 10 mL solution will contain \( \frac{10 \times 20}{100} \) grams of KCl.4. Simplify the calculation: - \( \frac{10 \times 20}{100} = 2 \) grams**Conclusion:**There are 2 grams of KCl in 10 mL of a 20% KCl solution.**Visual Aid Description:**The provided text does not contain any graphs or diagrams associated with the question. The main content is text-based and involves a straightforward calculation related to percentage concentration of a solution.

Given : Volume of solution = 10 ml Concentration of KCl in the solution = 20%

Answered: How many grams of KCl are there in 10…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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For this question it’s telling me use KCI which stands for potassium chloride so do I use KCl, (1 atom X 39.0983 Potassium) + (1 atom X 35.453 Chlorine) = (74.5513 g/mol) and use that with 10 ML of 20% Solution. I’ve been stuck on figuring out what I could do for this question. I want a long clarification and steps on it so it could help me know if I’m correct as I’m doing this question on my notebook.

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