I have a follow up question to my follow up question 3c: If the two people chosen are colorblind, shouldn't it be the conditional probability (E1|A) and (E2|A)? So we should be calculating P(E1|A)2 + P(E2|A)2 ? (0.9525)2 + (0.0476)2 = 0.9095

I have a follow up question to my follow up question 3c: If the two people chosen are colorblind, shouldn't it be the conditional probability (E1|A) and (E2|A)? So we should be calculating P(E1|A)2 + P(E2|A)2 ? (0.9525)2 + (0.0476)2 = 0.9095

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Related questions

Q: 3.57 Consider the experiment depicted by the Venn diagram, with the sample space S containing five…

A: As asked by you, I have answered the questions (C) and (D) only. Please find explanation below.…

Q: For 100 births, P(exactly 57 girls) = 0.0301 and P(57 or more girls) = 0.097. Is 57 girls in 100…

A: We have given. P(exactly 57 girls) = 0.0301 And P(57 or more girls) =0.097

Q: Suppose that E and F are two events and that N(E and F) = 440 and N(E) = 550. What is P(FIE)? %3D…

Q: The following table shows rooms offered by Hotel ABC. Twin Single Twin Executive Superior With 15 10…

A: The number of customers who will book an executive room with a bathtub is 6.The number of rooms that…

Q: A certain affects virus 0.1% of the population. A test used to detect the virus in a person is…

A: Solution

Q: Find the following probabilities: A. P(z > 1.96) B.P(-1.65<z<1.65) C.P(-2.33<z<o) Explain.

A: (A) The value of P(z > 1.96) is, Therefore, the required probability is, 0.0250.

Q: Could you please breakdown probability (P (1) for me which results in 6, 0.68, squared and results…

A: Given A solution based on binomial distribution,we need to explain how the probability P(1) is…

Q: Two cards are selected from a standard deck of 52 playing cards. The first card is not replaced…

A: Total Cards in deck = 52 Number of club in the deck = 13 Number of spade in the deck= 13 Probability…

Q: Suppose every bag of skittles has the following probability distributio P(green)=16%…

A: P(green)=16% P(Orange)=19% P(Purple)= 18% P(Red)=23% P(Yellow)=24%

Q: The average number of dropouts for a school district has been 305 per year with a standard devia-…

A: Hi! Thank you for the question. As per the honor code, we are allowed to answer three sub-parts at a…

Q: When tossing two fair coins, the probability of getting two tails P(TT)=1/4 What is the probability…

Q: The following is a table showing the results of a poll taken on campus. Will You Vote in the…

A: The objective of this question is to find the probability that a randomly selected student from this…

Q: d) For which temperature is the probability 0.075 that it will be exceeded during one day?

A: d) The probability value is 0.075.

Q: P(H ∩ B)=.375 P(H ∩ R)=.125 P(T ∩ B)=.375 P(T ∩ R)=.125 Using the same premise as the previous…

Q: Suppose P(A) = 0.2, P(B) - 0.45, and P(A n B) = 0.02. Find the following probabilities. P(A n B) =…

A: Given that, P(A) =0.2P(B) = 0.45P(A∩B)=0.02

Q: I would like to know why the approach to the problem below is wrong: When coin A is flipped, it…

A: The problem provides information about two coins, A and B, and their probabilities of landing on…

Q: If a group of 10 women is selected: What is the probability that at least two women will develop…

A: Answer n = 10p = 10% = 10/100 = 0.101- p = 1-0.10 = 0.90

Q: 10. 44% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S.…

A: Given: n = 10 , p = 0.44 Let X be the number of U.S. adults who have very little confidence in…

Q: Michael gave a probability answer as 24. What is wrong with an answer such as this?

A: According to the provided information, Michael gave a probability answer as 24.

Q: Runny Nose Fever Flu? N Y Y Y Y Y Y N Y Y Y Y Given above table, please use the Naive Bayes method…

Q: Assuming that P(green) = 0.75, what is the probability that among his 580 plants that the number of…

A: Given that , P(green) = 0.75 Total number of plants = 580 Let, X be the number of pees with green…

Q: Which would be the appropriate command in Excel to calculate the following? What is the probability…

A: The sample size n is 13.

Q: American Airlines' flights from Boston to Dallas are on time 90 % of the time. Suppose 8 flights are…

Q: The probability that a visit to a primary care physician’s (PCP) office results in either lab work…

A: event A: referrred to specialistevent B : require lab workP(A∪B) = 0.60P(A) = 0.35P(B) = 0.50P(A∩B)…

Q: When making random guesses on an 8 question quiz the probability of guessing correctly on any one…

Q: 8) (1 point) An event A will occur with probability 0.234. An event B will occur with prob- ability…

A: Solution

Q: The notation P(F E) means the probability of event given e

A: Formula: Let us consider A and B are two events, Then A|B represents that the event A given that the…

Q: 1. The Journal of the National Cancer Institute published the following results from a study they…

A: Introduction: The probability of an event, A is defined as the ratio of the number of cases…

Q: People with high blood pressure suffer from hypertension. Data on fasting blood sugar…

A: Given: Data on fasting blood sugar (milligrams/decilitre) and magnesium (milligrams/decilitre) in…

Q: obability that two mar

A: Combinations: This is a counting principle that allows to select r number of outcomes from a…

Question

I have a follow up question to my follow up question 3c:

If the two people chosen are colorblind, shouldn't it be the conditional probability (E₁|A) and (E₂|A)? So we should be calculating P(E₁|A)² + P(E₂|A)² ? (0.9525)² + (0.0476)² = 0.9095

Video Video

Expert Solution

Step 1: Information given

Suppose that 5% of men and 0.25% of women are color-blind from a population that is 50% men and 50% women.

So, let

Let $E subscript 1$ denot the event that men are chosen and

$E subscript 2$ denot the event that women are chosen , then we can say that P( $E subscript 1$ ) = 0.5 = P( $E subscript 2$ )

Let A be the event that a person chosen is colour blind, then P(A| $E subscript 1$ ) = 0.05 and P(A| $E subscript 2$ ) = 0.0025

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 6 images

SEE SOLUTION Check out a sample Q&A here

Similar questions

Leo is a very average golfer. The probability that he hits a bad shot at any time is 0.4, independent of the outcome of any other shot. In a round of golf, the probability that Leo's first bad shot is his fifth shot is Select one: O (0.4) (0.6)' O (0.4)5 O (0.6)* (0.4)' O (0.6) (0.4)'
The probability of a thunderstorm on Memorial Day is 0.13 and the probability of a thunderstorm on Independence Day is 0.59. Assuming that these two are Independent, what is the probability of thunderstorms on both Memorial and Independence Day?
For a class activity, your group has been assigned the task of generating a quiz question that requires use of the formula for conditional probability to compute P(B | A). Your group comes up with the following question "If P(A and B) = 0.40 and P(A) = 0.20, what is the value of P(B | A)?" What is wrong with this question? Hint: Consider the answer you get when using the correct formula, P(B | A) = P(A and B)/P(A).
Sub part d and e
For a class activity, your group has been assigned the task of generating a quiz question that requires use of the formula for conditional probability to compute P(B | A). Your group comes up with the following question "If P(A and B) = 0.40 and P(A) = 0.20, what is the value of P(B | A)?" What is wrong with this question? Hint: Consider the answer you get when using the correct formula, P(B | A) = P(A and B)/P(A). P(A and B) cannot be greater than P(A), because this yields a probability greater than 1 for the answer. P(A and B) should be larger. P(A and B) cannot be greater than P(A), because this yields a probability less than 0 for the answer. The question should be looking for P(A | B) not P(B | A).
If the P(A)=0.62,P(B)=0.25 and A and B are mutually exclusive, then the probability of neither A nor B occurring is o a. Cannot be determined o b. 0.715 O c. 87 o d. None of the suggested answers are correct O e.0.13
37
Based on the following table someone tells you “If you don’t use drugs, then the probability of you getting a negative test result is 0.993” Is that correct? Please explain why or why not.Drug Tests: Positive Test Negative TestSubject Uses Drugs: 44 6Subject Doesn’t Use Drugs: 90 860
If the weight (in grams) of cereal in a box of Lucky Charms is N(470,5), what is the probability that the box will contain less than the advertised weight of 453 g? (Round your answer to 4 decimal places.) Probability:???????????
The accompanying table shows the results from a test for a certain disease. Find the probability of selecting a subject with a negative test result, given that the subject has the disease. What would be an unfavorable consequence of this error? The individual actually O had the disease Yes No Positive 334 Negative 13 1176 EEE .E The probability is (Round to three decimal places as needed.) What would be an unfavorable consequence of this error? A. The test would be shown to be not effective. OB. The subject would experience needless stress and additional testing. Gradebo O C. The subject would not receive treatment and could spread the disease. Sco O D. The test would be shown to be not reliable. see scor