I have a follow up question to my follow up question 3c: If the two people chosen are colorblind, shouldn't it be the conditional probability (E1|A) and (E2|A)? So we should be calculating P(E1|A)2 + P(E2|A)2 ? (0.9525)2 + (0.0476)2 = 0.9095

I have a follow up question to my follow up question 3c: If the two people chosen are colorblind, shouldn't it be the conditional probability (E1|A) and (E2|A)? So we should be calculating P(E1|A)2 + P(E2|A)2 ? (0.9525)2 + (0.0476)2 = 0.9095

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Question

I have a follow up question to my follow up question 3c:

If the two people chosen are colorblind, shouldn't it be the conditional probability (E₁|A) and (E₂|A)? So we should be calculating P(E₁|A)² + P(E₂|A)² ? (0.9525)² + (0.0476)² = 0.9095

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Expert Solution

Step 1: Information given

Suppose that 5% of men and 0.25% of women are color-blind from a population that is 50% men and 50% women.

So, let

Let $E subscript 1$ denot the event that men are chosen and

$E subscript 2$ denot the event that women are chosen , then we can say that P( $E subscript 1$ ) = 0.5 = P( $E subscript 2$ )

Let A be the event that a person chosen is colour blind, then P(A| $E subscript 1$ ) = 0.05 and P(A| $E subscript 2$ ) = 0.0025

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