I don't understand why if (isSolution==true) or if (isSolution = true) cannot be a legal start of a if statement as the isSolution was declared and assigned false. Logically, it makes sense, but I don't understand how to work out the syntax. Java Code: import java.util.Scanner;public class LabProgram {public static void main(String[] args) {/* Type your code here. */Scanner scnr= new Scanner(System.in);int x1=scnr.nextInt();int y1=scnr.nextInt();int z1=scnr.nextInt();int x2=scnr.nextInt();int y2=scnr.nextInt();int z2=scnr.nextInt();int x=0;int y=0;Boolean isSolution=false; for (int i= -10; i < 11; i++) {for (int j= -10; i < 11; j++) {if ((x1 * i + y1 * j == z1) && (x2 * i + y2 * j == z2)) isSolution = true; x=i;y=j; break;}}} if (isSolution==true) {System.out.println("x= " +x+ "y= " +y); } else {System.out.println("There is no solution");}} Numerous engineering and scientific applications require finding solutions to a set of equations. Ex: 8x + 7y = 38 and 3x - 5y = -1 have asolution x = 3, y = 2. Given integer coefficients of two linear equations with variables x and y, use brute force to find an integer solution for xand y in the range -10 to 10.Ex: If the input is:8 7 383 -5 -1the output is:x = 3, y = 2Use this brute force approach:For every value of x from -10 to 10For every value of y from -10 to 10Check if the current x and y satisfy both equations. If so, output the solution, and finish.Ex: If no solution is found, output:There is no solutionYou can assume the two equations have no more than one solution.Note: Elegant mathematical techniques exist to solve such linear equations. However, for other kinds of equations or situations, brute forcecan be handy. Failed to compileLabProgram.java:27: error: illegal start of typeif (issolution==true) {LabProgram.java:27: error: expectedif (isSolution==true) {LabProgram.java:29: error: illegal start of type} else {3 errorS

You have misplaced the '}' of public static void main(String[] args) because of that the if…

Answered: I don't understand why if…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

I don't understand why if (isSolution==true) or if (isSolution = true) cannot be a legal start of a if statement as the isSolution was declared and assigned false. Logically, it makes sense, but I don't understand how to work out the syntax.

Java Code:

import java.util.Scanner;

public class LabProgram {
public static void main(String[] args) {
/* Type your code here. */Scanner scnr= new Scanner(System.in);

int x1=scnr.nextInt();
int y1=scnr.nextInt();
int z1=scnr.nextInt();
int x2=scnr.nextInt();
int y2=scnr.nextInt();
int z2=scnr.nextInt();
int x=0;
int y=0;
Boolean isSolution=false;

for (int i= -10; i < 11; i++) {
for (int j= -10; i < 11; j++) {
if ((x1 * i + y1 * j == z1) && (x2 * i + y2 * j == z2))
isSolution = true;
x=i;
y=j;
break;
}
}
}
if (isSolution==true) {
System.out.println("x= " +x+ "y= " +y);
} else {
System.out.println("There is no solution");
}
}

Numerous engineering and scientific applications require finding solutions to a set of equations. Ex: 8x + 7y = 38 and 3x - 5y = -1 have a
solution x = 3, y = 2. Given integer coefficients of two linear equations with variables x and y, use brute force to find an integer solution for x
and y in the range -10 to 10.
Ex: If the input is:
8 7 38
3 -5 -1
the output is:
x = 3, y = 2
Use this brute force approach:
For every value of x from -10 to 10
For every value of y from -10 to 10
Check if the current x and y satisfy both equations. If so, output the solution, and finish.
Ex: If no solution is found, output:
There is no solution
You can assume the two equations have no more than one solution.
Note: Elegant mathematical techniques exist to solve such linear equations. However, for other kinds of equations or situations, brute force
can be handy.

Failed to compile
LabProgram.java:27: error: illegal start of type
if (issolution==true) {
LabProgram.java:27: error: <identifier> expected
if (isSolution==true) {
LabProgram.java:29: error: illegal start of type
} else {
3 errorS

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