I don't think that the answer of this question is right!Cause it says Kc=Kp which means that 25=[HI]2/[H2]*[I2] and to get [HI]2 you should multiply the 25 with [H2]*[I2]Please correct me if I am wrong Explanation of SolutionFormula used:Kc|HI|²|H₂||2|Kckp[H₂ ] and [ 1₂ ] is a concentration at equilibrium.Calculation:|HI|²Kc = [1₂11/2]The equilibrium constant for Kc-Kp and the values are substituted by a equation,Kp|H₂||₂|25[0.286][0.286](=[= 305.638[HI] = √/305.638[HI] = 17.48 atm.ConclusionThe partial pressure of HI is 17.48 atm.

Answered: Image /qna-images/answer/435f703d-6a7e-495d-a01a-60d289d1f13e.jpg

I don't think that the answer of this question is right! Cause it says Kc=Kp which means that 25=[HI]2/[H2]*[I2] and to get [HI]2 you should multiply the 25 with [H2]*[I2] Please correct me if I am wrong

I don't think that the answer of this question is right! Cause it says Kc=Kp which means that 25=[HI]2/[H2][I2] and to get [HI]2 you should multiply the 25 with [H2][I2] Please correct me if I am wrong

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter13: Chemical Equilibrium

Section: Chapter Questions

Problem 2RQ: What is the law of mass action? Is it true that the value of K depends on the amounts of reactants...

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Question

100%

I don't think that the answer of this question is right!

Cause it says Kc=Kp which means that 25=[HI]²/[H₂]*[I₂]

and to get [HI]² you should multiply the 25 with [H₂]*[I₂]

Please correct me if I am wrong

Explanation of Solution
Formula used:
Kc
|HI|²
|H₂||2|
Kckp
[H₂ ] and [ 1₂ ] is a concentration at equilibrium.
Calculation:
|HI|²
Kc = [1₂11/2]
The equilibrium constant for Kc-Kp and the values are substituted by a equation,
Kp
|H₂||₂|
25
[0.286][0.286]
(=
[= 305.638
[HI] = √/305.638
[HI] = 17.48 atm.
Conclusion
The partial pressure of HI is 17.48 atm.

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