in the following four reactions (I-IV), two are invalid. (a) In the space below, identify the two invalid reactions by the corresponding numeral, and (b) explain why each is invalid or a synthetic trap. (Feel free to use a drawing to illustrate your point.) I. I. OH CuLi NaOH Br H20 I. ОН IV. 1. LAH 2. H20 HO

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In the following four reactions (I-IV), two are invalid. 

(a) Identify the two invalid reactions by the corresponding numeral, and (b) explain why each is invalid or a synthetic trap. (Feel free to use a drawing to illustrate your point.)

### Reaction I:
A starting compound with two ketone groups undergoes a reaction in the presence of NaOH and H₂O, resulting in a cyclic compound with an alcohol and a ketone group.

### Reaction II:
A compound with a bromine atom undergoes a reaction with a dialkylcuprate (R₂CuLi), resulting in an alkene.

### Reaction III:
A benzaldehyde derivative is reduced using 1. LAH (lithium aluminum hydride) and 2. H₂O, resulting in a primary alcohol.

### Reaction IV:
An amide group reacts with a combination of an amine (NH) and another base, yielding an imine.

**Notes on Diagrams:**
- **Reaction I Diagram:** Features a linear diketone transforming into a cyclized compound with hydroxyl and ketone groups.
- **Reaction III Diagram:** Shows a benzaldehyde derivative being reduced to form a benzyl alcohol using LAH as the reducing agent.
  
Analyze the mechanisms and identify errors or invalid expectations in the specified reactions.
Transcribed Image Text:In the following four reactions (I-IV), two are invalid. (a) Identify the two invalid reactions by the corresponding numeral, and (b) explain why each is invalid or a synthetic trap. (Feel free to use a drawing to illustrate your point.) ### Reaction I: A starting compound with two ketone groups undergoes a reaction in the presence of NaOH and H₂O, resulting in a cyclic compound with an alcohol and a ketone group. ### Reaction II: A compound with a bromine atom undergoes a reaction with a dialkylcuprate (R₂CuLi), resulting in an alkene. ### Reaction III: A benzaldehyde derivative is reduced using 1. LAH (lithium aluminum hydride) and 2. H₂O, resulting in a primary alcohol. ### Reaction IV: An amide group reacts with a combination of an amine (NH) and another base, yielding an imine. **Notes on Diagrams:** - **Reaction I Diagram:** Features a linear diketone transforming into a cyclized compound with hydroxyl and ketone groups. - **Reaction III Diagram:** Shows a benzaldehyde derivative being reduced to form a benzyl alcohol using LAH as the reducing agent. Analyze the mechanisms and identify errors or invalid expectations in the specified reactions.
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