I am having trouble finding the rest of the data for my precipitation Lab for percent yield of cobalt phosphate. The data I collected has already been imputed but cannot find the rest of the data. I need to use the given data I collected to find the other blank boxes in excel.
I am having trouble finding the rest of the data for my precipitation Lab for percent yield of cobalt phosphate. The data I collected has already been imputed but cannot find the rest of the data. I need to use the given data I collected to find the other blank boxes in excel.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I am having trouble finding the rest of the data for my precipitation Lab for percent yield of cobalt phosphate. The data I collected has already been imputed but cannot find the rest of the data. I need to use the given data I collected to find the other blank boxes in excel.
![### Precipitation Reactions – Background
This section provides instructions on how to calculate various aspects of a precipitation reaction.
#### A. Calculate the Mass of Dried Precipitate
#### B. Calculate the Moles of Na₃PO₄ Used
\[ \text{moles Na}_3\text{PO}_4 = (\text{molarity of Na}_3\text{PO}_4, \text{mole/L}) \times \left(\frac{\text{volume of Na}_3\text{PO}_4, \text{mL}}{1000}\right) \]
#### C. Calculate the Moles of Co(NO₃)₂ Used
\[ \text{moles Co(NO}_3\text{)}_2 = (\text{molarity of Co(NO}_3\text{)}_2, \text{mole/L}) \times \left(\frac{\text{volume of Co(NO}_3\text{)}_2, \text{mL}}{1000}\right) \]
#### D. Using the Balanced Chemical Equation, Convert the Moles of Na₃PO₄ to Moles of Precipitate
\[ \text{moles Na}_3\text{PO}_4 \times \left(\frac{\text{stoich. coeff. precipitate}}{\text{stoich. coeff. Na}_3\text{PO}_4}\right) = \text{moles of precipitate} \]
#### E. Using the Balanced Chemical Equation, Convert the Moles of Co(NO₃)₂ to Moles of Precipitate
\[ \text{moles Co(NO}_3\text{)}_2 \times \left(\frac{\text{stoich. coeff. precipitate}}{\text{stoich. coeff. Co(NO}_3\text{)}_2}\right) = \text{moles of precipitate} \]
#### F. What is the Limiting Reagent and What is the Theoretical Yield (Moles) of Precipitate?
#### G. Calculate the Molar Mass of the Precipitate
**Note:** The precipitate formed in this experiment is actually a hydrate!
**Precipitate \cdot X H₂O**
Perform literature research to determine the most common hydrate of the precipitate. Based on your answer, calculate the correct molar mass](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcf266520-407e-4b51-839c-e1d92d759be6%2F9d93c7c2-64e5-4168-993d-7ae5af2c435d%2Fulc576_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Precipitation Reactions – Background
This section provides instructions on how to calculate various aspects of a precipitation reaction.
#### A. Calculate the Mass of Dried Precipitate
#### B. Calculate the Moles of Na₃PO₄ Used
\[ \text{moles Na}_3\text{PO}_4 = (\text{molarity of Na}_3\text{PO}_4, \text{mole/L}) \times \left(\frac{\text{volume of Na}_3\text{PO}_4, \text{mL}}{1000}\right) \]
#### C. Calculate the Moles of Co(NO₃)₂ Used
\[ \text{moles Co(NO}_3\text{)}_2 = (\text{molarity of Co(NO}_3\text{)}_2, \text{mole/L}) \times \left(\frac{\text{volume of Co(NO}_3\text{)}_2, \text{mL}}{1000}\right) \]
#### D. Using the Balanced Chemical Equation, Convert the Moles of Na₃PO₄ to Moles of Precipitate
\[ \text{moles Na}_3\text{PO}_4 \times \left(\frac{\text{stoich. coeff. precipitate}}{\text{stoich. coeff. Na}_3\text{PO}_4}\right) = \text{moles of precipitate} \]
#### E. Using the Balanced Chemical Equation, Convert the Moles of Co(NO₃)₂ to Moles of Precipitate
\[ \text{moles Co(NO}_3\text{)}_2 \times \left(\frac{\text{stoich. coeff. precipitate}}{\text{stoich. coeff. Co(NO}_3\text{)}_2}\right) = \text{moles of precipitate} \]
#### F. What is the Limiting Reagent and What is the Theoretical Yield (Moles) of Precipitate?
#### G. Calculate the Molar Mass of the Precipitate
**Note:** The precipitate formed in this experiment is actually a hydrate!
**Precipitate \cdot X H₂O**
Perform literature research to determine the most common hydrate of the precipitate. Based on your answer, calculate the correct molar mass
Transcribed Image Text:### Experimental Data Set
#### Mass Measurements
- **Mass of dish & Paper (g)**
- Solution 3: 5895.32
- Solution 4: 5843.1
- Solution 9: 5857.02
- **Mass dish, paper, product (g)**
- Solution 3: 5895.7
- Solution 4: 5843.7
- Solution 9: 5857.66
- **Mass of dried product**
- Solution 3: 0.24
#### Molarity
- **Molarity of Na₃PO₄:** 0.6
- **Molarity of Co(NO₃)₂:** 11.3
#### Volume Measurements
- **mL of Na₃PO₄**
- Solution 3: 10
- Solution 4: 10
- Solution 9: 10
- **mL of Co(NO₃)₂**
- Solution 3: 4
- Solution 4: 6
- Solution 9: 12
#### Calculations
- **Moles of Co(NO₃)₂**
- Solution 9: 4
- **Theoretical yield if Na₃PO₄:** (Not provided)
- **Theoretical yield if Co(NO₃)₂:** (Not provided)
- **Limiting Reagent:** (Not provided)
- **MolMass of product hydrate:** (Not provided)
- **Theoretical Yield in grams:** (Not provided)
#### Results
- **Percent Yield:** (Not provided)
- **Predicted color of filtrate:** (Not provided)
### Notes
The data set outlines the mass of dishes, papers, and products for three solutions, alongside molarity data for two compounds involved in the experiments. Calculated values like moles, theoretical yields, and percent yields require additional input or further calculations.
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