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A 2.37 gram sample of a KCI and KCIO3 mixture was found to contain 0.01611 mol of KCIO3. What is the percent by mass of KCIO3 in the original mixture? Report your answer with three significant figures.

A 2.37 gram sample of a KCI and KCIO3 mixture was found to contain 0.01611 mol of KCIO3. What is the percent by mass of KCIO3 in the original mixture? Report your answer with three significant figures.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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### Determining Percent by Mass of KClO₃ in a Mixture **Problem Statement:** A 2.37 gram sample of a KCl and KClO₃ mixture was found to contain 0.01611 mol of KClO₃. What is the percent by mass of KClO₃ in the original mixture? Report your answer with three significant figures. **Figure/Diagram:** There is no diagram or graph associated with this problem. **Calculation Steps:** 1. **Molar Mass Calculation** The molar mass of KClO₃ (Potassium Chlorate) is calculated as follows: - Potassium (K): 39.10 g/mol - Chlorine (Cl): 35.45 g/mol - Oxygen (O): 3 × 16.00 g/mol - Total Molar Mass of KClO₃: 39.10 + 35.45 + 48.00 = 122.55 g/mol 2. **Mass of KClO₃ Calculation** Using the number of moles of KClO₃ provided: Mass of KClO₃ = moles of KClO₃ × molar mass of KClO₃ = 0.01611 mol × 122.55 g/mol = 1.975 g (to three significant figures) 3. **Percent by Mass Calculation** Percent by Mass of KClO₃ = (mass of KClO₃ / total mass of the mixture) × 100 = (1.975 g / 2.37 g) × 100 = 83.4% (to three significant figures) **Final Answer:** The percent by mass of KClO₃ in the original mixture is **83.4%**. *Note: Click Submit to complete this assessment.* **Reference:** Based on the principles of analytical chemistry and stoichiometry.
Transcribed Image Text:### Determining Percent by Mass of KClO₃ in a Mixture **Problem Statement:** A 2.37 gram sample of a KCl and KClO₃ mixture was found to contain 0.01611 mol of KClO₃. What is the percent by mass of KClO₃ in the original mixture? Report your answer with three significant figures. **Figure/Diagram:** There is no diagram or graph associated with this problem. **Calculation Steps:** 1. **Molar Mass Calculation** The molar mass of KClO₃ (Potassium Chlorate) is calculated as follows: - Potassium (K): 39.10 g/mol - Chlorine (Cl): 35.45 g/mol - Oxygen (O): 3 × 16.00 g/mol - Total Molar Mass of KClO₃: 39.10 + 35.45 + 48.00 = 122.55 g/mol 2. **Mass of KClO₃ Calculation** Using the number of moles of KClO₃ provided: Mass of KClO₃ = moles of KClO₃ × molar mass of KClO₃ = 0.01611 mol × 122.55 g/mol = 1.975 g (to three significant figures) 3. **Percent by Mass Calculation** Percent by Mass of KClO₃ = (mass of KClO₃ / total mass of the mixture) × 100 = (1.975 g / 2.37 g) × 100 = 83.4% (to three significant figures) **Final Answer:** The percent by mass of KClO₃ in the original mixture is **83.4%**. *Note: Click Submit to complete this assessment.* **Reference:** Based on the principles of analytical chemistry and stoichiometry.
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