What is the formula (solve for x) for the original hydrated sample of copper (II) sulphate? You weigh a sample of CuS04 · XH2O. After you heat the sample, you find that the mass of the anhydrous salt is 1.47g. What is the value of x? CONTEXT Mass of just anhydrous compound = mass of anhydrous compound - mass of beaker and rod = 108.34g - 106.87g = 1.47g = original compound mass - anhydrous compound mass = 3.00g - 1.47g 1.53g Mass of just water %3D

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What is the formula (solve for x) for the original hydrated sample of copper (II)
sulphate?
You weigh a sample of CuSO4 · XH2O. After you heat the sample, you find that the mass of
the anhydrous salt is 1.47g. What is the value of x?
CONTEXT
Mass of just anhydrous compound
= mass of anhydrous compound
rod
mass of beaker and
108.34g - 106.87g
= 1.47g
%3D
%3D
= original compound mass - anhydrous compound mass
= 3.00g - 1.47g
= 1.53g
Mass of just water
Transcribed Image Text:What is the formula (solve for x) for the original hydrated sample of copper (II) sulphate? You weigh a sample of CuSO4 · XH2O. After you heat the sample, you find that the mass of the anhydrous salt is 1.47g. What is the value of x? CONTEXT Mass of just anhydrous compound = mass of anhydrous compound rod mass of beaker and 108.34g - 106.87g = 1.47g %3D %3D = original compound mass - anhydrous compound mass = 3.00g - 1.47g = 1.53g Mass of just water
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