Hypothetically, the reaction H2 + 2IC1 → I2 + 2HC1 is first order in [H2] and second order in [ICl]. Based on the first fast step given below and the fact that the second step is the slow step, propose a second-step mechanism, and show that it conforms to the experimentally determined reaction order. Assume that [I2] does not affect the reaction rate. H2 + 2ICI → I2 + 2HC1 Fast: 2ICI → I2 + 2C1 Slow:

Hypothetically, the reaction H2 + 2IC1 → I2 + 2HC1 is first order in [H2] and second order in [ICl]. Based on the first fast step given below and the fact that the second step is the slow step, propose a second-step mechanism, and show that it conforms to the experimentally determined reaction order. Assume that [I2] does not affect the reaction rate. H2 + 2ICI → I2 + 2HC1 Fast: 2ICI → I2 + 2C1 Slow:

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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