The reaction 2NOB → 2NO + Br2 exhibits the rate law Rate = k[NOB1]²= A[NOB1] At where k= 1.0 × 10-°M'·s¯l at 25°C. This reaction is run where the initial concentration of NOBr ([NOB1]o) is 1.00 x 10-1M. The [NO] after 1.00 hour has passed is
The reaction 2NOB → 2NO + Br2 exhibits the rate law Rate = k[NOB1]²= A[NOB1] At where k= 1.0 × 10-°M'·s¯l at 25°C. This reaction is run where the initial concentration of NOBr ([NOB1]o) is 1.00 x 10-1M. The [NO] after 1.00 hour has passed is
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Step 1
Introduction:
The given reaction is
Given data ;
- k is rate constant
- is intial concentration of NOBr
- t is reaction time
from stochiometry of reaction Concentration of NOBr is equal to concentration of NO
The unit of rate constant is so given reaction is second order reaction .
Integration of the second-order rate law is
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