Hydrogen peroxide and the iodide ion react in acidic solution as follows:
H2O2(aq) + 3I- (aq) + 2H+ (aq) =====➔I -(3aq ) + 2H2O(l)
The kinetics of this reaction were studied by following the decay of the concentration of H2O2 and constructing plots of ln[H2O2] versus time. All the plots were linear and all solutions had [H2O2]o = 8.0 x10-4 mol/L. The slopes of these straight lines depended on the initial concentrations of I- and H-. The results follow:
[I_]0 |
[H+]0 |
Slope |
(mol/L) |
(mol/L) |
(/min) |
0.1000 |
0.0400 |
-0.120 |
0.3000 |
0.0400 |
-0.360 |
0.4000 |
0.0400 |
-0.480 |
0.0750 |
0.0200 |
-0.0760 |
0.0750 |
0.0800 |
-0.118 |
0.0750
|
0.1600 |
-0.174 |
The rate law for this reaction has the form;
Rate = -d[H2O2]/dt = (k1 +k2[H+]) [I-] m[H2O2]n
a. Specify the orders of this reaction with respect to [H2O2] and [I-].
b. Calculate the values of the rate constants k1 and k
c. What reason could there be for the two-term dependence of the rate on [H+]?
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