Hydrogen cyanide, HCN, is prepared from ammonia, air, and natural gas (CH4) by the following process: 2NH3 (g) + 30, (9) + 2CH, (9) → 2HCN(g) + 6H, O(9) Hydrogen cyanide is used to prepare sodium cyanide, which is used in part to obtain gold from gold-containing rock. If a reaction vessel contains 4.90 g NH3, 11.0 g O2, and 5.17 g CH4, what is the maximum mass in grams of hydrogen cyanide that could be made, assuming the reaction goes to completion as written? Mass = g HCN

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Hydrogen cyanide, HCN, is prepared from ammonia, air, and natural gas (CH4) by the following process:
2NH3 (g) + 30, (9) + 2CH, (9) → 2HCN(g) + 6H, O(9)
Hydrogen cyanide is used to prepare sodium cyanide, which is used in part to obtain gold from gold-containing rock. If a reaction vessel contains 4.90 g NH3, 11.0 g O2, and 5.17
g CH4, what is the maximum mass in grams of hydrogen cyanide that could be made, assuming the reaction goes to completion as written?
Mass =
g HCN
Transcribed Image Text:Hydrogen cyanide, HCN, is prepared from ammonia, air, and natural gas (CH4) by the following process: 2NH3 (g) + 30, (9) + 2CH, (9) → 2HCN(g) + 6H, O(9) Hydrogen cyanide is used to prepare sodium cyanide, which is used in part to obtain gold from gold-containing rock. If a reaction vessel contains 4.90 g NH3, 11.0 g O2, and 5.17 g CH4, what is the maximum mass in grams of hydrogen cyanide that could be made, assuming the reaction goes to completion as written? Mass = g HCN
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