h(x) = 8 sedx + 1) 4

Algebra and Trigonometry (6th Edition)
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ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Identify the asymptotes in the displayed domain of the graph you selected above. (Enter your answers as a comma-separated list of equations.)

 
please help me find the correct answer, I had previously asked this question and got the answer: 1, 5, −3, −5 but it is wrong. (please help me understand why)
The given mathematical function is:

\[ h(x) = 8 \sec \left( \frac{\pi}{4}(x + 1) \right) \]

This function involves the secant trigonometric function, which is the reciprocal of the cosine function. The expression inside the secant function is a linear transformation of \( x \). The transformation includes a horizontal shift of \( -1 \) and a horizontal stretch by a factor of \( \frac{4}{\pi} \). The \( 8 \) outside the secant function acts as a vertical stretch.
Transcribed Image Text:The given mathematical function is: \[ h(x) = 8 \sec \left( \frac{\pi}{4}(x + 1) \right) \] This function involves the secant trigonometric function, which is the reciprocal of the cosine function. The expression inside the secant function is a linear transformation of \( x \). The transformation includes a horizontal shift of \( -1 \) and a horizontal stretch by a factor of \( \frac{4}{\pi} \). The \( 8 \) outside the secant function acts as a vertical stretch.
The image displays the graph of the function \(y = \frac{1}{x^2}\). This graph consists of symmetrical curves with respect to the y-axis, and it's defined for all \(x \neq 0\).

### Detailed Explanation:

- **Graph Behavior:**
  - As \(x\) approaches 0 from the positive or negative side, \(y\) approaches infinity. This describes a vertical asymptote along the y-axis.
  - As \(x\) moves away from zero, in both positive and negative directions, the value of \(y\) decreases and approaches zero, but never actually reaches zero.

- **Axes and Scales:**
  - The x-axis is labeled with intervals from -8 to 8.
  - The y-axis is labeled with intervals from -16 to 16. 

- **Quadrants:**
  - The graph is shown in the first and second quadrants since the function produces positive \(y\)-values for any real \(x\).

This graph helps in understanding the behavior of reciprocal functions and their properties, such as asymptotes and symmetry.
Transcribed Image Text:The image displays the graph of the function \(y = \frac{1}{x^2}\). This graph consists of symmetrical curves with respect to the y-axis, and it's defined for all \(x \neq 0\). ### Detailed Explanation: - **Graph Behavior:** - As \(x\) approaches 0 from the positive or negative side, \(y\) approaches infinity. This describes a vertical asymptote along the y-axis. - As \(x\) moves away from zero, in both positive and negative directions, the value of \(y\) decreases and approaches zero, but never actually reaches zero. - **Axes and Scales:** - The x-axis is labeled with intervals from -8 to 8. - The y-axis is labeled with intervals from -16 to 16. - **Quadrants:** - The graph is shown in the first and second quadrants since the function produces positive \(y\)-values for any real \(x\). This graph helps in understanding the behavior of reciprocal functions and their properties, such as asymptotes and symmetry.
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Given that: h(x)=8secπ4(x+1)

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