Hurricane damage: In August and September 2005, Hurricanes Katrina and Rita caused extraordinary flooding in New Orleans. Louisiana. Many homes were severely damaged or destroyed, and of those that survived, many required extensive cleaning. It was thought that cleaning flood-damaged homes might present a health hazard due to the large amounts of mold present in many of the homes. In a sample of 3 70 residents of Orleans Parish who had participated in the cleaning of one or more homes, 28 had experienced symptoms of wheezing, and in a sample of 173 residents who had not participated in the cleaning, 30 reported wheezing symptoms (numbers read from a graph). Can you conclude that there is a difference betvween the proportion of residents with wheezing symptoms who cleaned flood-damaged homes and those who did not participate in the cleaning? Let P. denote the proportion of residents with wheezing symptoms who had cleaned flood-damaged homes and p, denote the proportion of residents with wheezing symptoms who had not cleaned flood-damanged homes. Use the a = 0.01 level of significance and the P-value method with the TI-84 Plus calculator. Part 1 of 4 State the null and alternate hypotheses. H P - P H P1 * P2 This hypothesis test is a two-tailed test. Part: 1/4 Part 2 of 4 Find the P-value. Round the answer to four decimal places. P-value =
Hurricane damage: In August and September 2005, Hurricanes Katrina and Rita caused extraordinary flooding in New Orleans. Louisiana. Many homes were severely damaged or destroyed, and of those that survived, many required extensive cleaning. It was thought that cleaning flood-damaged homes might present a health hazard due to the large amounts of mold present in many of the homes. In a sample of 3 70 residents of Orleans Parish who had participated in the cleaning of one or more homes, 28 had experienced symptoms of wheezing, and in a sample of 173 residents who had not participated in the cleaning, 30 reported wheezing symptoms (numbers read from a graph). Can you conclude that there is a difference betvween the proportion of residents with wheezing symptoms who cleaned flood-damaged homes and those who did not participate in the cleaning? Let P. denote the proportion of residents with wheezing symptoms who had cleaned flood-damaged homes and p, denote the proportion of residents with wheezing symptoms who had not cleaned flood-damanged homes. Use the a = 0.01 level of significance and the P-value method with the TI-84 Plus calculator. Part 1 of 4 State the null and alternate hypotheses. H P - P H P1 * P2 This hypothesis test is a two-tailed test. Part: 1/4 Part 2 of 4 Find the P-value. Round the answer to four decimal places. P-value =
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Hurricane damage: In August and September 2005, Hurricanes Katrina and Rita caused extraordinary flooding in New Orleans.
Louisiana. Many homes were severely damaged or destroyed, and of those that survived, many required extensive cleaning. It
was thought that cleaning flood-damaged homes might present a health hazard due to the large amounts of mold present in many
of the homes. In a sample of 3 70 residents of Orleans Parish who had participated in the cleaning of one or more homes, 28 had
experienced symptoms of wheezing, and in a sample of 173 residents who had not participated in the cleaning,
vwheezing symptoms (numbers read from a graph). Can you conclude that there is a difference betvween the proportion of
residents with wheezing symptoms who cleaned flood-damaged homes and those who did not participate in the cleaning? Let P
denote the proportion of residents with wheezing symptoms who had cleaned flood-damaged homes and p, denote the proportion
30
reported
of residents with wheezing symptoms who had not cleaned flood-damanged homes. Use the a= 0.01 level of significance and the
P-value method with the TI-84 Plus calculator.
Part 1 of 4
State the null and alternate hypotheses.
H P = P:
H P1 * P2
This hypothesis test is a two-tailed
test.
Part: 1/4
Part 2 of 4
Find the P-value. Round the answer to four decimal places.
P-value =
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