How should you write a reduce function that calculates the sum of the first 10 numbers of the geometric progression given by the following recurrence relation: an 2 an-1 where ao = 1? Choose all that apply. To use reduce you need to import it from functools: from functools import reduce sum_ = reduce (lambda x, y: y+x, [2**x for x in range(10)]) sum_reduce (lambda x, y: yx, [2"x for x in range(1,11)]) sum reduce (lambda x, y: x + y. [2**i for i in range(10)]) sum_reduce (lambda x, y: yx, [2 for x in range(1,11)]) sum_ = reduce (((x, x+y) for x in [2**i for i in range(10)]), [2**x for x in range(10)])

How should you write a reduce function that calculates the sum of the first 10 numbers of the geometric progression given by the following recurrence relation: an 2 an-1 where ao = 1? Choose all that apply. To use reduce you need to import it from functools: from functools import reduce sum_ = reduce (lambda x, y: y+x, [2x for x in range(10)]) sum_reduce (lambda x, y: yx, [2"x for x in range(1,11)]) sum reduce (lambda x, y: x + y. [2i for i in range(10)]) sum_reduce (lambda x, y: yx, [2 for x in range(1,11)]) sum_ = reduce (((x, x+y) for x in [2i for i in range(10)]), [2x for x in range(10)])

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Concept explainers

Recurrence relation

A recurrence relation or recursive relation is an equation that represents a function in terms of the values of its smaller inputs. Every recurrence relation T(n) is a recursive function of integer n and consists of a base case and a recursive case.

Question

How should you write a reduce function that calculates the sum of
the first 10 numbers of the geometric progression given by the
following recurrence relation: an = 2 an-1 where ao = 1? Choose all
that apply. To use reduce you need to import it from functools:
from functools import reduce
sum_ = reduce (lambda x, y: y+x, [2**x for x in range(10)])
sum_ = reduce (lambda x, y: y*x, [2*x for x in range(1,11)])
sum_ = reduce (lambda x, y: x + y, [2**i for i in range(10)])
sum_ = reduce (lambda x, y: y*x, [2 for x in range(1,11)])
sum_ = reduce (((x, x+y) for x in [2**i for i in range(10)]), [2**x for x in
range(10)])

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