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Given the code snippet below which returns a list of all the permutations of a string "inp" with length x. Find the following: - The recurrence relation of the running time of func(inp)? (Assume that appending to a list and string concatenation both run in constant time or O(1). Hint: Determine the number of returned elements first) - The worst case time complexity of func(inp). (Be as precise as possible with factorials. In other words, between any factorials such as n! (n+1)! and (n-1)!, only the most precise answer will be acepted)

Given the code snippet below which returns a list of all the permutations of a string "inp" with length x. Find the following: - The recurrence relation of the running time of func(inp)? (Assume that appending to a list and string concatenation both run in constant time or O(1). Hint: Determine the number of returned elements first) - The worst case time complexity of func(inp). (Be as precise as possible with factorials. In other words, between any factorials such as n! (n+1)! and (n-1)!, only the most precise answer will be acepted)

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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WILL GIVE THUMBS UP IF CORRECT AND WITH EXPLANATION.
WILL GIVE THUMBS DOWN IF INCORRECT OR INSUFFICIENT EXPLANATION.

Given the code snippet below which returns a list of all the permutations of a string "inp" with length x. Find the following:

- The recurrence relation of the running time of func(inp)? (Assume that appending to a list and string concatenation both run in constant time or O(1). Hint: Determine the number of returned elements first)

- The worst case time complexity of func(inp). (Be as precise as possible with factorials. In other words, between any factorials such as n! (n+1)! and (n-1)!, only the most precise answer will be acepted)

def func(inp): if len(inp) < 1: return [""] list = [] for x in range(len(inp)): for y in func(inp[:x] + inp[x+1:]): list.append (inp[x] + y) return list print(func (input()))
Transcribed Image Text:def func(inp): if len(inp) < 1: return [""] list = [] for x in range(len(inp)): for y in func(inp[:x] + inp[x+1:]): list.append (inp[x] + y) return list print(func (input()))
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